在python中使用scipy的curvefit拟合Boxcar函数的问题 [英] Problems fitting to boxcar function using scipy's curvefit in python

问题描述

我无法使这种棚车工作……我得到 OptimizeWarning：无法估计参数的协方差
category = OptimizeWarning） ，并且输出系数为

 从scipy导入numpy as np $ b $b。optimizeimport curve_fit 
 def box（x，* p）：
高度，中心，宽度= p 
返回高度*（center-width / 2< x）*（x< center + width / 2）
 
x = np.linspace（-5,5）
y =（-2.5  
 coeff，var_matrix = curve_fit（box，x，y，p0 = [1,0,2]）
  

输出系数为[1.04499699，0.，2.]，不是第三个系数没有改变。

我怀疑这种函数形式不适合curve_fit使用的levenberg-marquardt算法，这有点烦人，因为我喜欢这个函数。在mathematica中，指定一个蒙特卡洛优化将变得微不足道。

解决方案

我怀疑此函数形式不适合curve_fit使用的levenberg-marquardt算法

您是对的。通常，基于梯度的优化不适用于具有尖锐边缘的函数。通过稍微扰动功能参数并查看装配质量的变化来估算梯度。但是，如果边缘不与数据点交叉，则稍微移动边缘将导致零梯度：

• A：很容易拟合振幅，因为高度的微小变化会立即导致残差的变化。


• B：很难拟合边缘，因为位置的微小变化不会影响残差（除非变化大到足以使边缘越过数据点）。

使用随机方法会更好。 Scipy具有

I can't get this boxcar fit working...I get " OptimizeWarning: Covariance of the parameters could not be estimated category=OptimizeWarning)", and the output coefficients are not improved beyond the starting guess.

import numpy as np
from scipy.optimize import curve_fit
def box(x, *p):
    height, center, width = p
    return height*(center-width/2 < x)*(x < center+width/2)

x = np.linspace(-5,5)
y = (-2.5<x)*(x<2.5) + np.random.random(len(x))*.1

coeff, var_matrix = curve_fit(box, x, y, p0=[1,0,2])

The output coefficients are [ 1.04499699, 0., 2.], not that the third one has not even been changed.

I suspect that this functional form is not amenable to the levenberg-marquardt algorithm used by curve_fit, which is kind of annoying because I like this function. In mathematica it would be trivial to specify a monte carlo optimization, instead.

解决方案

I suspect that this functional form is not amenable to the levenberg-marquardt algorithm used by curve_fit

You are right. Generally, gradient-based optimizations are not well suited for functions with sharp edges. The gradient is estimated by perturbing the function parameters just a little and looking at the change in fitting quality. However, moving an edge just a little results in zero gradient if it does not cross a data point:

• A: it is easy to fit the amplitude because a small change in height immediaterly leads to a change in the residuals.
• B: it is hard to fit edges because a small change in position does not affect the residuals (unless the change is big enough to make the edge cross a data point).

Using a stochastic method should work better. Scipy has the differential_evolution function, which uses genetic algorithm and is therefore related to monte-carlo methods. However, it is less trivial to use than curve_fit. You need to specify a cost function and ranges for the parameters:

res = differential_evolution(lambda p: np.sum((box(x, *p) - y)**2),  # quadratic cost function
                             [[0, 2], [-5, 5], [0.1, 10]])  # parameter bounds

It's still a one-liner :)

coeff, var_matrix = curve_fit(box, x, y, p0=[1,0,2])

res = differential_evolution(lambda p: np.sum((box(x, *p) - y)**2), [[0, 2], [-5, 5], [0.1, 10]])

plt.step(x, box(x, *coeff), where='mid', label='curve_fit')
plt.step(x, box(x, *res.x), where='mid', label='diff-ev')
plt.plot(x, y, '.')
plt.legend()

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