如何通过引用更改data.table中每个组中的最后一个值 [英] How to change the last value in each group by reference, in data.table

问题描述

对于按站点分组的data.table DT，按时间t排序，我需要更改每个组中变量的最后一个值。我认为应该可以使用：=进行引用，但是我还没有找到一种可行的方法。

For a data.table DT grouped by site, sorted by time t, I need to change the last value of a variable in each group. I assume it should be possible to do this by reference using :=, but I haven't found a way that works yet.

示例数据：

require(data.table)   # using 1.8.11 
DT <- data.table(site=c(rep("A",5), rep("B",4)),t=c(1:5,1:4),a=as.double(c(11:15,21:24)))
setkey(DT, site, t)
DT
#    site t  a
# 1:    A 1 11
# 2:    A 2 12
# 3:    A 3 13
# 4:    A 4 14
# 5:    A 5 15
# 6:    B 1 21
# 7:    B 2 22
# 8:    B 3 23
# 9:    B 4 24

所需的结果是更改a的最后一个值在每个组中，例如为999，因此结果如下：

The desired result is to change the last value of a in each group, for example to 999, so the result looks like:

#    site t   a
# 1:    A 1  11
# 2:    A 2  12
# 3:    A 3  13
# 4:    A 4  14
# 5:    A 5 999
# 6:    B 1  21
# 7:    B 2  22
# 8:    B 3  23
# 9:    B 4 999

似乎应该使用.I和/或.N，但是我有找不到有效的表格。在与.I [.N]相同的语句中使用：=会产生错误。下面给出了要进行分配的行号：

It seems like .I and/or .N should be used, but I haven't found a form that works. The use of := in the same statement as .I[.N] gives an error. The following gives me the row numbers where the assignment is to be made:

DT[, .I[.N], by=site]
#    site V1
# 1:    A  5
# 2:    B  9

但我似乎无法将其与：=分配一起使用。以下给出错误：

but I don't seem to be able to use this with a := assignment. The following give errors:

DT[.N, a:=999, by=site]
# Null data.table (0 rows and 0 cols)

DT[, .I[.N, a:=999], by=site]
# Error in `:=`(a, 999) : 
#   := and `:=`(...) are defined for use in j, once only and in particular ways.
#  See help(":="). Check is.data.table(DT) is TRUE.

DT[.I[.N], a:=999, by=site]
# Null data.table (0 rows and 0 cols)

有没有一种方法可以通过引用data.table来做到这一点？还是在R中用另一种方法更好地完成了？

Is there a way to do this by reference in data.table? Or is this better done another way in R?

推荐答案

当前您可以使用：

DT[DT[, .I[.N], by = site][['V1']], a := 999]
# or, avoiding the overhead of a second call to `[.data.table`
set(DT, i = DT[,.I[.N],by='site'][['V1']], j = 'a', value = 999L)

替代方法：

使用替换 ...

DT[, a := replace(a, .N, 999), by = site]

或将替换项转移到RHS中，并用<$ c包装$ c> {} 并返回完整向量

or shift the replacement to the RHS, wrapped by {} and return the full vector

DT[, a := {a[.N] <- 999L; a}, by = site]

或使用 mult ='last'并充分利用逐个的优势。

or use mult='last' and take advantage of by-without-by. This requires the data.table to be keyed by the groups of interest.

 DT[unique(site), a := 999, mult = 'last']

有功能请求＃2793

DT[, a[.N] := 999]

但这尚未实现

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