使用Seaborn的分布图的局部阴影 [英] Partial shade of distribution plot using Seaborn

问题描述

以下简单代码：

import numpy as np
import seaborn as sns
dist = np.random.normal(loc=0, scale=1, size=1000)
ax = sns.kdeplot(dist, shade=True);

产生以下图像：

< a href = https://i.stack.imgur.com/b8kYj.png rel = nofollow noreferrer>

我只想对所有内容进行阴影处理（或保留一些x值）。最简单的方法是什么？我已经准备好使用Seaborn以外的其他东西。

I would like to only shade everything right (or left to some x value). What is the simplest way? I am ready to use something other than Seaborn.

推荐答案

调用 ax = sns.kdeplot（dist ，shade = True）， ax.get_lines（）的最后一行对应于kde密度曲线：

After calling ax = sns.kdeplot(dist, shade=True), the last line in ax.get_lines() corresponds to the kde density curve:

ax = sns.kdeplot(dist, shade=True)
line = ax.get_lines()[-1]

您可以使用 line.get_data 提取与该曲线相对应的数据：

You can extract the data corresponding to that curve using line.get_data:

x, y = line.get_data()

一旦有了数据，就可以例如将与 x> 0 ，选择这些点并调用 ax.fill_between ：

Once you have the data, you can, for instance, shade the region corresponding to x > 0 by selecting those points and calling ax.fill_between:

mask = x > 0
x, y = x[mask], y[mask]
ax.fill_between(x, y1=y, alpha=0.5, facecolor='red')

---

---

import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt
dist = np.random.normal(loc=0, scale=1, size=1000)
ax = sns.kdeplot(dist, shade=True)
line = ax.get_lines()[-1]
x, y = line.get_data()
mask = x > 0
x, y = x[mask], y[mask]
ax.fill_between(x, y1=y, alpha=0.5, facecolor='red')
plt.show()

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