在Python中获取最后一个星期日和星期六的日期 [英] get the last sunday and saturday's date in python

问题描述

希望利用 datetime 来获取上周的开始和结束日期，即星期日至星期六。

Looking to leverage datetime to get the date of beginning and end of the previous week, sunday to saturday.

所以，如果今天是13年8月12日，我想定义一个要打印的函数：

So, if it's 8/12/13 today, I want to define a function that prints:

上周日是8/4 / 2013年和上星期六是2013年8月10日

我该如何写呢？

编辑：好的，所以似乎有一些关于边缘情况的问题。对于星期六，我希望在同一周，对于其他任何事情，我希望紧接今天 日期之前的日历周。

okay, so there seems to be some question about edge cases. For saturdays, I want the same week, for anything else, I'd like the calendar week immediately preceding today's date.

推荐答案

datetime.date.weekday 返回星期一的 0 。

尝试以下操作：

>>> import datetime
>>> today = datetime.date.today()
>>> today
datetime.date(2013, 8, 13)
>>> idx = (today.weekday() + 1) % 7 # MON = 0, SUN = 6 -> SUN = 0 .. SAT = 6
>>> idx
2
>>> sun = today - datetime.timedelta(7+idx)
>>> sat = today - datetime.timedelta(7+idx-6)
>>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat)
'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013'

如果允许使用 python-dateutil ：

>>> import datetime
>>> from dateutil import relativedelta
>>> today = datetime.datetime.now()
>>> start = today - datetime.timedelta((today.weekday() + 1) % 7)
>>> sat = start + relativedelta.relativedelta(weekday=relativedelta.SA(-1))
>>> sun = sat + relativedelta.relativedelta(weekday=relativedelta.SU(-1))
>>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat)
'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013'

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