在javascript中将对象星期日至星期六进行排序 [英] sorting object Sunday to Saturday in javascript

问题描述

你好，我认识这个问题的每个人都被问了几次，但是我没有得到确切答案.

Hello Everyone i know this question is asked several time but i am not getting exact answer to my question.

// I have array of object like this
data=[
        // "sunday": 1, // << sunday is first day of week      
      {DayOfWeek:"Saturday", TotalCount:30},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Sunday", TotalCount:18}, 
      {DayOfWeek:"Wednesday", TotalCount:20}        
    ];


// I need sorted like this:
data=[
        // "sunday": 1, // << sunday is first day of week
      {DayOfWeek:"Sunday", TotalCount:18},  
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Wednesday", TotalCount:20},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Saturday", TotalCount:30}  
    ];

我尝试过此方法，但无法获得预期的结果. 它通过像

I tried this one but I am not able to get the expected result. it is giving me a sorted array by starting alphabet like

星期五，星期六.

var sorter = { //星期天":1，//<<星期日是一周的第一天 周日":1 星期一":2 星期二":3， 星期三":4 星期四":5 星期五":6 星期六":7 }

var sorter = { // "sunday": 1, // << sunday is first day of week "sunday": 1, "monday": 2, "tuesday": 3, "wednesday": 4, "thursday": 5, "friday": 6, "saturday": 7 }

  var result= data.sort(function sortByDay(a, b) {
    var day1 = a.DayOfWeek.toLowerCase();
    var day2 = b.DayOfWeek.toLowerCase();
    return sorter[day1] > sorter[day2];
  });

请帮助我，谢谢.

推荐答案

您可以像以前一样使用订单对象对它进行排序，但是需要区别

You can sort it with an object for the order, as you already had, but you need the difference

return order[a.DayOfWeek] - order[b.DayOfWeek];

作为排序回调的返回值.

as a return value for the sort callback.

var data = [{ DayOfWeek: "Saturday", TotalCount: 30 }, { DayOfWeek: "Friday", TotalCount: 10 }, { DayOfWeek: "Monday", TotalCount: 23 }, { DayOfWeek: "Sunday", TotalCount: 18 }, { DayOfWeek: "Wednesday", TotalCount: 20 }],
    order = { Sunday: 1, Monday: 2, Tuesday: 3, Wednesday: 4, Thursday: 5, Friday: 6, Saturday: 7 };

data.sort(function (a, b) {
    return order[a.DayOfWeek] - order[b.DayOfWeek];
});
document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>');

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