如何使用两种不同的日期/时间格式来确定以后的格式? [英] How do two different date/time formats to determine which one is later?

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问题描述

我正在获取类似的日期/时间格式:

I'm getting date/time formats like this to compare:

08:18:00 07/11/2013

7/11/2013 9:11:00 AM

操作方法我将它们中的每一个都转换为一种格式,这样我就可以像这样编写PHP以找出哪个是以后的日期/时间?

How do I convert each one of them to a format so I can write PHP like this to find out which one is a later date/time?

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format.
$time2 = "7/11/2013 9:11:00 AM";

$time_one = $mytimeconvertdate_time_first($time1);
$time_two = $mytimeconvertdate_date_first($time2);

if ($time_two > $time_one) {
   echo "time_two is later" . "\n";
}  else {
   echo "time_one is later" . "\n";
}

我已经尝试过,但是第二个值不包含日期信息:

I have tried this, but the second value doesn't contain date info:

<?php
date_default_timezone_set('America/New_York');

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format.
$time2 = "7/11/2013 9:11:00 AM";

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y H:i:s", $time2);
var_dump($dt1);
var_dump($dt2);
if ($dt1 < $dt2) echo "The first is earlier";

?>

输出为:

object(DateTime)#1 (3) {
  ["date"]=>
  string(19) "2013-07-11 08:18:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
bool(false)

更正为:

<?php
date_default_timezone_set('America/New_York');

//注意:一个是24小时制,另一个是12小时制,带有am / pm。

// Note: "One is 24-hour format while the other is 12-hour with am/pm. "

// $time1 will always be in HH:MM:SS MM/DD/YYYY format.
$time1 = "08:18:00 07/11/2013";

// $time2 will always be in MM/DD/YYYY HH:MM:SS format. 
$time2 = "7/11/2013 9:11:00 AM";

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y g:i:s a", $time2);
var_dump($dt1);
var_dump($dt2);
if ($dt1 < $dt2) echo "The first is earlier" . "\n";

?>


object(DateTime)#1 (3) {
  ["date"]=>
  string(19) "2013-07-11 08:18:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
object(DateTime)#2 (3) {
  ["date"]=>
  string(19) "2013-07-11 09:11:00"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "America/New_York"
}
The first is earlier


推荐答案

使用 DateTime :: createFromFormat 从格式化文本创建两个 DateTime 实例。然后,您可以直接比较实例,以查找时间更早的实例。

Use DateTime::createFromFormat to create two DateTime instances from the formatted text. You can then compare the instances directly to find which is earlier in time.

$dt1 = DateTime::createFromFormat("H:i:s m/d/Y", $time1);
$dt2 = DateTime::createFromFormat("m/d/Y g:i:s a", $time2);

if ($dt1 < $dt2) echo "The first is earlier";
// etc

这篇关于如何使用两种不同的日期/时间格式来确定以后的格式?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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