在SQL Server pt2中，将日期范围分成每月一行 [英] Split date range into one row per month in SQL Server pt2

问题描述

这个问题与此帖子有关：在SQL Server中将日期范围划分为每月一排

This question relates to this post: Split date range into one row per month in sql server

但是我对Stackoverflow并不陌生，并且不允许新用户对提供的解决方案发表评论。这就是为什么我现在将其添加为新问题。

But I'm new to Stackoverflow and new users are not allowed to place comments to provided solutions.That's why I am now adding this as a new question.

问题是这样的：

我有一个表，该表有两列，分别为 from_date和 to_date

I have a table with two column called "from_date" and "to_date"

该表看起来像这样：

表格（我无法在此处嵌入图片，因此请点击链接）

我想要这样的结果：-

from_date || to_date

----------- ------------

from_date || to_date
----------- ------------

2013-11- 25 || 2013-11-30

2013-11-25 || 2013-11-30

2013-12-01 || 2013-12-05

2013-12-01 || 2013-12-05

该日期从2013-11-25到2013-11-30，另一个日期从2013-12-01到2013-12 -05 ...是否可以这样拆分？

That date is splits from 2013-11-25 to 2013-11-30 and another date split from 2013-12-01 to 2013-12-05... Is it possible to split like this ?

Aaron Bertrand的解决方案是：

Aaron Bertrand's solution is this:

DECLARE @d TABLE(from_date DATE, to_date DATE);

INSERT @d VALUES ('2013-11-25','2013-12-05');

;WITH n(n) AS 
(
    SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1 
    FROM sys.all_columns
),
d(n,f,t,md,bp,ep) AS 
(
    SELECT n.n, d.from_date, d.to_date, 
           DATEDIFF(MONTH, d.from_date, d.to_date),
           DATEADD(MONTH, n.n, DATEADD(DAY, 1-DAY(from_date), from_date)),
           DATEADD(MONTH, n.n+1, DATEADD(DAY, 0-DAY(from_date), from_date))
    FROM n 
    INNER JOIN @d AS d ON d.to_date >= DATEADD(MONTH, n.n-1, d.from_date)
)
SELECT original_from_date = f, original_to_date = t, 
       new_from_date = CASE n WHEN 0  THEN f ELSE bp END,
       new_to_date   = CASE n WHEN md THEN t ELSE ep END 
FROM d 
WHERE md >= n
ORDER BY original_from_date, new_from_date;

结果：

original_from_date   original_to_date   new_from_date   new_to_date
------------------   ----------------   -------------   -----------
2013-11-25           2013-12-05         2013-11-25      2013-11-30
2013-11-25           2013-12-05         2013-12-01      2013-12-05

Aaron Bertrand's答案是一个超级强大的查询，但似乎只有在开始日期是31天的一个月之后的一个月内，它才能很好地工作。如果将开始日期更改为例如2013-5-25（从4月开始，只有30天），则new_to_date值不正确：所有整月突然最多不能超过30天，则：

Aaron Bertrand's answer is a super powerful query, but it seems it only works well if the startdate is in a month following a month with 31 days. If you change the startdate to, for example, 2013-5-25 (following April, with only 30 days), the new_to_date values are incorrect: all full months suddenly get a max of 30 days then:

original_from_date  original_to_date    new_from_date   new_to_date
2013-05-25          2013-12-05          2013-05-25      2013-05-30
2013-05-25          2013-12-05          2013-06-01      2013-06-30
2013-05-25          2013-12-05          2013-07-01      2013-07-30
2013-05-25          2013-12-05          2013-08-01      2013-08-30
2013-05-25          2013-12-05          2013-09-01      2013-09-30
2013-05-25          2013-12-05          2013-10-01      2013-10-30
2013-05-25          2013-12-05          2013-11-01      2013-11-30
2013-05-25          2013-12-05          2013-12-01      2013-12-05

任何人都可以编辑查询以便结束日期是正确的（28、30、31天和2月29日为leap日），无论星期一开始日期在哪里？我不知道该怎么做。

Can anyone edit the query so that end dates are correct (28,30,31 days, and 29 feb leap) regardless of what month the start date is in? I can't figure out how to do it.

非常感谢Martijn Vermunt

Many thanks, Martijn Vermunt

推荐答案

已提供答案，查询已被编辑并变得完美。谢谢 @Aaron Bertrand
用于更新查询！

The answer has been provided, the query has been edited and made perfect. Thank you @Aaron Bertrand for updating the query!

DECLARE @d TABLE(from_date DATE, to_date DATE);

INSERT @d VALUES ('2013-11-25','2013-12-05');

;WITH n(n) AS 
(
SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1 FROM sys.all_columns
),
d(n,f,t,md,bp,ep) AS  
(
SELECT n.n, d.from_date, d.to_date, 
DATEDIFF(MONTH, d.from_date, d.to_date),
DATEADD(MONTH, n.n, DATEADD(DAY, 1-DAY(from_date), from_date)),
DATEADD(DAY, -1, DATEADD(MONTH, 1, DATEADD(MONTH, n.n, 
 DATEADD(DAY, 1-DAY(from_date), from_date))))
FROM n INNER JOIN @d AS d 
ON d.to_date >= DATEADD(MONTH, n.n-1, d.from_date)
)
SELECT original_from_date = f, original_to_date = t, 
new_from_date = CASE n WHEN 0  THEN f ELSE bp END,
new_to_date   = CASE n WHEN md THEN t ELSE ep END 
FROM d WHERE md >= n
ORDER BY original_from_date, new_from_date;

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