在sql server中每月将日期范围拆分为一行 [英] Split date range into one row per month in sql server

问题描述

我有一个包含两列的表格，名为from_date"和to_date"

I have a table with two column called "from_date" and "to_date"

    the table look like:-

我想要这样的结果:-

from_date            to_date   
-----------         ------------  
2013-11-25           2013-11-30
2013-12-01           2013-12-05

那个日期从 2013-11-25 拆分到 2013-11-30，另一个日期从 2013-12-01 拆分到 2013-12-05... 可以这样拆分吗?

That date is splits from 2013-11-25 to 2013-11-30 and another date split from 2013-12-01 to 2013-12-05... Is it possible to split like this ?

推荐答案

这是闰年安全的，可以处理其他答案目前没有的日期范围.

This is leap year safe and handles date ranges the other answers currently don't.

DECLARE @d TABLE(from_date DATE, to_date DATE);

INSERT @d VALUES ('2013-11-25','2013-12-05');

;WITH n(n) AS 
(
  SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1 FROM sys.all_columns
),
d(n,f,t,md,bp,ep) AS 
(
  SELECT n.n, d.from_date, d.to_date, 
    DATEDIFF(MONTH, d.from_date, d.to_date),
    DATEADD(MONTH, n.n, DATEADD(DAY, 1-DAY(from_date), from_date)),
    DATEADD(DAY, -1, DATEADD(MONTH, 1, DATEADD(MONTH, n.n, 
      DATEADD(DAY, 1-DAY(from_date), from_date))))
 FROM n INNER JOIN @d AS d 
 ON d.to_date >= DATEADD(MONTH, n.n-1, d.from_date)
)
SELECT original_from_date = f, original_to_date = t, 
  new_from_date = CASE n WHEN 0  THEN f ELSE bp END,
  new_to_date   = CASE n WHEN md THEN t ELSE ep END 
FROM d WHERE md >= n
ORDER BY original_from_date, new_from_date;

结果:

original_from_date   original_to_date   new_from_date   new_to_date
------------------   ----------------   -------------   -----------
2013-11-25           2013-12-05         2013-11-25      2013-11-30
2013-11-25           2013-12-05         2013-12-01      2013-12-05

具有更长日期范围和闰年的 SQLFiddle 演示

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