将日期时间舍入到前一个小时 [英] Round down datetime to previous hour

问题描述

如何将日期时间舍入到前一个小时？例如：

How to round down datetime to previous hour? for example:

print datetime.now().replace(microsecond=0)
>> 2017-01-11 13:26:12.0

向下舍入到前一个小时： 2017-01-11 12：00：00.0

round down to previous hour: 2017-01-11 12:00:00.0

推荐答案

鉴于您要四舍五入到小时数，您只需替换 microsecond ， second 和分钟，带有零：

Given you want to round down to the hour, you can simply replace microsecond, second and minute with zeros:

print(datetime.now().replace(microsecond=0, second=0, minute=0))

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如果想要四舍五入到上一个小时（如示例 2017-01-11 13：26：12.0 所示为 2017-01-11 12：00：00.0 ），替换 microsecond ， second 并将分钟设为零，然后减去一小时：

---

If you want to round down to the previous hour (as stated in the example 2017-01-11 13:26:12.0 to 2017-01-11 12:00:00.0), replace microsecond, second and minute with zeros, then subtract one hour:

from datetime import datetime, timedelta

print(datetime.now().replace(microsecond=0, second=0, minute=0) - timedelta(hours=1))

shell中的示例：

Example in the shell:

$ python3
Python 3.5.2 (default, Nov 17 2016, 17:05:23) 
[GCC 5.4.0 20160609] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> from datetime import datetime, timedelta
>>> print(datetime.now().replace(microsecond=0, second=0, minute=0) - timedelta(hours=1))
2017-01-11 16:00:00

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