如何检查DART中是否存在给定的日期? [英] How to check if a given Date exists in DART?
问题描述
如果您将不存在/不真实的日期(例如: 20181364(2018/13/64))传递到DateTime(构造函数或解析方法)中,则不会引发任何异常。而是返回计算出的DateTime。
If you pass a non-existing/non-real date like: '20181364' (2018/13/64) into DateTime (constructor or parse-method), no exception is thrown. Instead a calculated DateTime is returned.
示例:
'20181364'-> 2019-03-05 00:00:00.000
Example: '20181364' --> 2019-03-05 00:00:00.000
如何检查给定日期是否确实存在/有效?
How can I check if a given date really exists/is valid?
我尝试使用DartPad解决此问题(未成功),
I tried to solve this using DartPad (without success), so no Flutter doctor output required here.
void main() {
var inputs = ['20180101', // -> 2018-01-01 00:00:00.000
'20181231', // -> 2018-12-31 00:00:00.000
'20180230', // -> 2018-03-02 00:00:00.000
'20181301', // -> 2019-01-01 00:00:00.000
'20181364'];// -> 2019-03-05 00:00:00.000
inputs.forEach((input) => print(convertToDate(input)));
}
String convertToDate(String input){
return DateTime.parse(input).toString();
}
如果有某种方法可以检查给定值日期确实存在/有效,例如:
It would be great if there exist some kind of method to check if a given date really exists/is valid, e.g.:
- DateTime中的validate函数
- 另一个lib不使用DateTime.parse()进行验证
您将如何解决?
推荐答案
您可以将解析后的日期转换为原始格式的字符串,然后比较其是否与输入匹配。
You can convert parsed date to string with original format and then compare if it's matching the input.
void main() {
var inputs = ['20180101', // -> 2018-01-01 00:00:00.000
'20181231', // -> 2018-12-31 00:00:00.000
'20180230', // -> 2018-03-02 00:00:00.000
'20181301', // -> 2019-01-01 00:00:00.000
'20181364'];// -> 2019-03-05 00:00:00.000
inputs.forEach((input) {
print("$input is valid string: ${isValidDate(input)}");
});
}
bool isValidDate(String input) {
final date = DateTime.parse(input);
final originalFormatString = toOriginalFormatString(date);
return input == originalFormatString;
}
String toOriginalFormatString(DateTime dateTime) {
final y = dateTime.year.toString().padLeft(4, '0');
final m = dateTime.month.toString().padLeft(2, '0');
final d = dateTime.day.toString().padLeft(2, '0');
return "$y$m$d";
}
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