如何比较数据库中从Excel获取记录的两个日期? [英] How to compare two dates from database which gets records from Excel?
问题描述
可能重复:
如何将日期从一种格式转换为另一种格式
我有一个包含5列的电子表格。其中之一包含日期列,格式为02年12月12日。
I am having a spreadsheet with 5 columns. One of that contain date column with format 02-Dec-10.
当我将Excel工作表提供给数据库时,它存储为空的日期为0000-00-00 00: 00:00。
When I feed that Excel sheet to database it stores as empty date as 0000-00-00 00:00:00.
如何将其存储为日期?
这是使用CSV文件向数据库提供数据的代码
This is the code to feed data to database using CSV file
$date = date("d-m-Y");
$databasetable = "sample";
$fieldseparator = ",";
$lineseparator = "\n";
$csvfile = "../uploads/" . basename( $_FILES['file']['name']);
$addauto = 0;
$save = 1;
$outputfile = "../temp/output.sql";
if(!file_exists($csvfile)) {
#echo $csvfile;
echo "File not found. Make sure you specified the correct path.\n";
return 0;
exit;
}
$file = fopen($csvfile,"r");
if(!$file) {
#echo "Error opening data file.\n";
return 0;
exit;
}
$size = filesize($csvfile);
if(!$size) {
echo "File is empty.\n";
return 0;
exit;
}
$csvcontent = fread($file,$size);
fclose($file);
$lines = 0;
$queries = "";
$linearray = array();
foreach(split($lineseparator,$csvcontent) as $line) {
$lines++;
$line = trim($line," \t");
$line = str_replace("\r","",$line);
$line = str_replace("'","\'",$line);
$linearray = explode($fieldseparator,$line);
$linemysql = implode("','",$linearray);
if($addauto)
$query = "insert into $databasetable values('','$linemysql');";
else
$query = "insert into $databasetable values('$linemysql');";
$queries .= $query . "\n";
@mysql_query($query);
}
@mysql_close($con);
if($save) {
$file2 = fopen($outputfile,"w");
if(!$file2) {
echo "Error writing to the output file.\n";
return 0;
}
else {
fwrite($file2,$queries);
fclose($file2);
return 1;
}
}
//echo "Found a total of $lines records in this csv file.\n";
推荐答案
只要您使用的是1970年之间的日期仅在2038年, strtotime()
应该可以安全使用。在每个日期列上执行此操作,以将其转换为mySQL的 YYYY-MM-DD
日期格式:
As long as you're working with dates between 1970 and 2038 only, strtotime()
should be safe to use. Do this on each date column to convert it to mySQL's YYYY-MM-DD
date format:
$column = date("Y-m-d", strtotime($column)); // Will return 2010-12-02
确定日期列的最简单方法是指定他们手动。否则,您必须先开始获取表的结构,并查看哪些列是 DATE
或 DATETIME
的列。
the easiest way to determine a date column would be to specify them manually. Otherwise, you'd have to start fetching the table's structure beforehand, and looking which columns are DATE
or DATETIME
ones.
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