使用python计数输入的位数 [英] Counting number of digits of input using python

问题描述

我正在尝试计算输入的位数。但是，每当我输入 10 或 11 或任何两位数字时，输出为 325 。为什么它不起作用？

I am trying to count the number of digits of an input. However, whenever I input 10 or 11 or any two digit number, the output is 325. Why doesn't it work?

inputnumber = int(input())
countnumber = inputnumber
digitcount = 0
while countnumber > 0:
    digitcount += 1
    countnumber = countnumber/10

print(digitcount) 
# result is 325 when input is 10 or 11

推荐答案

您的错误主要发生在这里：

Your error mainly happened here:

countnumber=countnumber/10

您打算进行整数除法。 Python 3 中的单斜杠除法始终是 float或 real除法，它会在需要时产生一个float值和一个小数部分。

Note that you are intending to do integer division. Single-slash division in Python 3 is always "float" or "real" division, which yields a float value and a decimal part if necessary.

将其替换为双斜杠除法，即整数除法： countnumber = countnumber // 10 。在这种情况下，每次执行整数除法时，都会切除最右边的数字。

Replace it with double-slash division, which is integer division: countnumber = countnumber // 10. Each time integer division is performed in this case, the rightmost digit is cut.

您还必须注意输入是否为0。数字0被认为是一位，而不是零。

You also have to watch out if your input is 0. The number 0 is considered to be one digit, not zero.

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