C ++通过定界符分割字符串并保持定界符在结果中 [英] C++ spliting string by delimiters and keeping the delimiters in result

问题描述

我正在寻找一种使用C ++中的regex通过多个定界符来分割字符串的方法，但又不会丢失输出中的定界符，而是将定界符与分割后的部分保持顺序，例如：

I'm looking for a way to split string by multiple delimiters using regex in C++ but without losing the delimiters in output, keeping the delimiters with splitted parts in order, for example:

输入

aaa，bbb.ccc，ddd-eee;

aaa,bbb.ccc,ddd-eee;

输出

aaa，bbb。 ccc，ddd-eee；

aaa , bbb . ccc , ddd - eee ;

我已经找到了一些解决方案，但都是在C＃或Java中，寻找一些C ++解决方案，最好不要使用Boost。

I've found some solutions for this but all in C# or java, looking for some C++ solution, preferably without using Boost.

推荐答案

您可以在 regex_iterator 。例如，如果您知道分隔符是逗号，句点，分号和连字符，则可以使用捕获分隔符或一系列非分隔符的正则表达式：

You could build your solution on top of the example for regex_iterator. If, for example, you know your delimiters are comma, period, semicolon, and hyphen, you could use a regex that captures either a delimiter or a series of non-delimiters:

([.,;-]|[^.,;-]+)

将其拖放到示例代码中，最后得到类似的内容：

Drop that into the sample code and you end up with something like this:

#include <iostream>
#include <string>
#include <regex>

int main ()
{
  // the following two lines are edited; the remainder are directly from the reference.
  std::string s ("aaa,bbb.ccc,ddd-eee;");
  std::regex e ("([.,;-]|[^.,;-]+)");   // matches delimiters or consecutive non-delimiters

  std::regex_iterator<std::string::iterator> rit ( s.begin(), s.end(), e );
  std::regex_iterator<std::string::iterator> rend;

  while (rit!=rend) {
    std::cout << rit->str() << std::endl;
    ++rit;
  }

  return 0;
}

尝试替换您喜欢的任何其他正则表达式。

Try substituting in any other regular expressions you like.

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