R在保留两个定界符之前（和之后）strsplit [英] R strsplit before ( and after ) keeping both delimiters

问题描述

我有一个类似于以下内容的字符串：

I have a string that looks like the following:

x <- "01(01)121210(01)0001"

我想将其拆分为向量，以便获得以下信息：

I want to split this into a vector so that i get the following:

[1] "0" "1" "(01)" "1" "2" "1" "2" "1" "0" "(01)" "0" "0" "0" "1"

|）可以是[|]或{|}，括号之间的位数可以是2个或更多。

The (|) could be [|] or {|} and the number of digits between the brackets can be 2 or more.

我一直在尝试通过分隔首先放在括号中：

I've been trying to do this by separating on the brackets first:

unlist(strsplit(x, "(?<=[\\]\\)\\}])", perl=T))
[1] "01(01)" "121210(01)" "0001"

or unlist(strsplit(x, "(?<=[\\[\\(\\{])", perl=T))
[1] "01(" "01)121210(" "01)0001"

但我找不到将两者结合在一起的方法。 b $ b然后，我希望拆分不包含方括号的元素。

but I can't find a way to combine the two together. Then, I was hoping to split the elements not containing the brackets.

如果有人可以帮我解决这个问题或知道更优雅

I'd be really grateful if someone can help me out with this or know of a more elegant way to do this.

非常感谢！

推荐答案

此是另一种方式：

unlist(strsplit(x, '\\([^)]*\\)(*SKIP)(*F)|(?=)', perl=T))
# [1] "0"    "1"    "(01)" "1"    "2"    "1"    "2"    "1"    "0"    "(01)" "0"    "0"    "0"    "1" 

\\（[^）] * \\）匹配括号中的任何内容，而（* SKIP）（* F ）告诉正则表达式引擎在此模式上失败，如果它在字符串中找到该模式，请不要使用<$另一侧的替代模式来重新测试字符串的该部分c $ c> | 。 | 另一侧的模式是（？=），它与字符之间的空格匹配。

\\([^)]*\\) matches anything in parentheses, and (*SKIP)(*F) tells the regular expression engine to fail on this pattern and if it finds that pattern in the string, do not re-test that part of the string using the alternative pattern on the other side of the |. The pattern on the other side of the | is (?=), and this matches the space between characters.

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