是否可以声明一个包含另一个常量数组的常量数组？ [英] Is it possible do Declare a constant array that includes another constant array?

问题描述

我想做这样的事情：

const

  MyFirstConstArray: array[0..1] of string = ('Hi', 'Foo');
  MySecondConstArrayWhichIncludesTheFirstOne: array[0..2] of string = 
    MyFirstConstArray + ('Bar');

基本上我想要以下结果：

Basically I want the following result:

MyFirstConstArray -> ('Hi', 'Foo');
MySecondConstArrayWhichIncludesTheFirstOne -> ('Hi', 'Foo', 'Bar');

有可能吗？

推荐答案

AFAIK，您不能这样做。

但是，如果目标是确保只声明一次实际的常量字符串，建议您声明各个字符串，然后将它们分组为数组：

AFAIK, you can't do that.
But if the goal is to ensure you declare your actual constant string only once, I suggest you declare the individual strings and then group them in arrays:

const
  MyConst1 = 'Hi';
  MyConst2 = 'Foo';
  MyConst3 = 'Bar';
  MyFirstConstArray: array[0..1] of string = (MyConst1, MyConst2);
  MySecondConstArrayWhichIncludesTheFirstOne: array[0..2] of string = 
    (MyConst1, MyConst2, MyConst3);

BTW，您的语法不正确，必须精确调整数组元素的类型。

BTW, your syntax is incorrect, you have to precise the type of the array elements.

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