如何比较XML文件 [英] How to compare XML files

问题描述

我有两个由某些工具生成的XML文件（XSD）。

该工具不会保留元素的顺序，因此尽管内容相等，但将其作为文本进行比较会导致文件是不同的。

是否有一些工具可以在比较之前对元素进行排序，并可以对文档进行文本比较？
当然，排序需要递归进行。

I have two XML files (XSD) which are generated by some tool.
The tool doesn't preserve the order of elements so although the content is equal comparing it as text will result as the files are different.
Is there some tool that can sort the elements before comparing and will enable text comparison of the documents? Of course the sorting needs to be done recursively.

数据示例：

文件A：

Data example:
File A:

<xml>
  <A/>
  <B/>
</xml>

文件B：

<xml>
  <B/>
  <A/>
</xml>

推荐答案

我遇到了类似的问题，但最终发现：< a href = http://superuser.com/questions/79920/how-can-i-diff-two-xml-files> http://superuser.com/questions/79920/how-can-i-diff -two-xml-files

I had a similar problem and I eventually found: http://superuser.com/questions/79920/how-can-i-diff-two-xml-files

该帖子建议先进行规范的XML排序，然后再进行比较。如果您使用的是Linux，Mac或安装了Cygwin之类的Windows，则下面的命令应该适合您：

That post suggests doing a canonical XML sort then doing a diff. The following should work for you if you are on Linux, Mac, or if you have Windows with something like Cygwin installed:

$ xmllint --c14n FileA.xml > 1.xml
$ xmllint --c14n FileB.xml > 2.xml
$ diff 1.xml 2.xml

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