Groovy:比较SOAP响应和XML文件 [英] Groovy : Compare SOAP Response with XML file
问题描述
这是我的代码:
import org.custommonkey.xmlunit.Stuff
import org.xmlunit.Stuff
// ExpectedString是我的xml转换为文本,相同对于ResponseString
Diff diff = DiffBuilder.compare(ExpectedString)
.withTest(ResponseString)
.ignoreComments()
.ignoreWhitespace()
.checkForSimilar ()
.withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byName))
.build();
assertFalse(XML similar+ diff.toString(),diff.hasDifferences())
因此,正如你所看到的,我使用了DefaultNodeMatcher,我使用了XMLUnit2.0 ...没有结果(甚至不会忽略顺序或比较时发生异常错误)
是否有解决方案?解决这个问题
由于我不顾一切地找到一个直接的,我可以排序我的XML和我的肥皂响应,所以我可以有一个简单的差异?有没有一种方法可以按字母顺序逐行排序?如果是的话,怎么样?
谢谢大家!
更新:
以下是我简化的XML结构
< body>
< stuff>
< miniStuff>< / miniStuff>
< miniStuff>< / miniStuff>
< / stuff>
<服务>
<服务>
< tag1> ValueA< / tag1>
< tag2> ValueAA< / tag2>
< / Service>
<服务>
< tag1> ValueB< / tag1>
< tag2> ValueBB< / tag2>
< / Service>
< / services>
< / body>
我的问题是我无法保证ValueA是第一个而不是第二个
以下是您可能要查找的内容:use ByNameAndTextRecSelector
withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
单元测试:
@Test
public void testDiffOrder(){
final String control =
< r>
< ser>
< t1> a< / t1>
< t2> b< / t2>
< / ser>
< ser>
< t1> d< / t1>
< t2> ; e< / t2>
< / ser>
< / r>
final String test =
< r>
< ser>
< t1> d< / t1>
< t2> e< / t2>
< / ser>
< ser>
< t1> a< / t1>
< t2> b< / t2>
< / ser>
< / r>
Diff diff = DiffBuilder.compare(Input.fromString(control))
.withTest(Input.fromString(test))
.ignoreComments ()
.ignoreWhitespace()
.checkForSimilar()
.withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
.build()
assertFalse(XML differ+ diff.toString(),diff.hasDifferences())
}
点数到@bodewig。
来自 here
更新:更多groovified版本与OP原始XML片段。
import org.xmlunit.builder.DiffBuilder
import org.xmlunit.builder.Input
import org.xmlunit.diff.ByNameAndTextRecSelector
import org.xmlunit.diff.DefaultNodeMatcher
import org.xmlunit.diff.ElementSelectors
def control = <身体GT;
< stuff>
< miniStuff />
< miniStuff />
< / stuff>
<服务>
<服务>
< tag1> ValueB< / tag1>
< tag2> ValueBB< / tag2>
< / Service>
<服务>
< tag1> ValueA< / tag1>
< tag2> ValueAA< / tag2>
< / Service>
< /服务>
< / body>
def test =< body>
< stuff>
< miniStuff />
< miniStuff />
< / stuff>
<服务>
<服务>
< tag1> ValueA< / tag1>
< tag2> ValueAA< / tag2>
< / Service>
<服务>
< tag1> ValueB< / tag1>
< tag2> ValueBB< / tag2>
< / Service>
< /服务>
< / body>
def myDiff = DiffBuilder.compare(Input.fromString(control))
.withTest(Input.fromString(test))
.checkForSimilar ()
.withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
.build()
println myDiff.toString()
println myDiff.hasDifferences()
assert!myDiff.hasDifferences()
I want to compare in groovy code my Soap Response with xml file ignoring order :
Here is my code :
import org.custommonkey.xmlunit.Stuff
import org.xmlunit.Stuff
//ExpectedString is my xml converted to text, same for ResponseString
Diff diff = DiffBuilder.compare(ExpectedString)
.withTest(ResponseString)
.ignoreComments()
.ignoreWhitespace()
.checkForSimilar()
.withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byName))
.build();
assertFalse("XML similar " + diff.toString(), diff.hasDifferences())
So, as you can see, I used DefaultNodeMatcher, I used XMLUnit2.0 ... with no result (even not ignoring order or having exception error while comparing)
Is there a solution ? to resolve this
As I'm desperate to find a direct one, can I sort my xml and my soap response so i can have a simple diff ? is there a way to sort it line by line alphabetically ? If yes, how ?
Thank you guys !
Update :
Here is my XML structure simplified
<body>
<stuff>
<miniStuff></miniStuff>
<miniStuff></miniStuff>
</stuff>
<Services>
<Service>
<tag1>ValueA</tag1>
<tag2>ValueAA</tag2>
</Service>
<Service>
<tag1>ValueB</tag1>
<tag2>ValueBB</tag2>
</Service>
</services>
</body>
My problem is I can't guarantee that ValueA is the first one and not the second
Here is the one you might looking for: use ByNameAndTextRecSelector
withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
Unit Test:
@Test
public void testDiffOrder() {
final String control = """
<r>
<ser>
<t1>a</t1>
<t2>b</t2>
</ser>
<ser>
<t1>d</t1>
<t2>e</t2>
</ser>
</r>"""
final String test = """
<r>
<ser>
<t1>d</t1>
<t2>e</t2>
</ser>
<ser>
<t1>a</t1>
<t2>b</t2>
</ser>
</r>"""
Diff diff = DiffBuilder.compare(Input.fromString(control))
.withTest(Input.fromString(test))
.ignoreComments()
.ignoreWhitespace()
.checkForSimilar()
.withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
.build()
assertFalse("XML differ " + diff.toString(), diff.hasDifferences())
}
Credits to @bodewig. Sample from here
UPDATE: more groovified versionwith OPs original xml snippet.
import org.xmlunit.builder.DiffBuilder
import org.xmlunit.builder.Input
import org.xmlunit.diff.ByNameAndTextRecSelector
import org.xmlunit.diff.DefaultNodeMatcher
import org.xmlunit.diff.ElementSelectors
def control = """<body>
<stuff>
<miniStuff />
<miniStuff />
</stuff>
<Services>
<Service>
<tag1>ValueB</tag1>
<tag2>ValueBB</tag2>
</Service>
<Service>
<tag1>ValueA</tag1>
<tag2>ValueAA</tag2>
</Service>
</Services>
</body>"""
def test = """<body>
<stuff>
<miniStuff />
<miniStuff />
</stuff>
<Services>
<Service>
<tag1>ValueA</tag1>
<tag2>ValueAA</tag2>
</Service>
<Service>
<tag1>ValueB</tag1>
<tag2>ValueBB</tag2>
</Service>
</Services>
</body>"""
def myDiff = DiffBuilder.compare(Input.fromString(control))
.withTest(Input.fromString(test))
.checkForSimilar()
.withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
.build()
println myDiff.toString()
println myDiff.hasDifferences()
assert !myDiff.hasDifferences()
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