将Bash脚本cd到目录中的最新目录中 [英] Bash script to cd into newest directory within a directory

问题描述

我正在尝试向正在编写的数据收集bash脚本中添加功能。目的是指向一个特定的目录，然后在父目录中cd到最新目录。

I am trying to add a function to a data collection bash script I am writing. The intention would be to point to a specific directory, and then cd into the NEWEST directory within the parents.

伪代码：

cd top_dir
    for each dir in top_dir:
      age = dir.age
      if age < least_age:
        least_age = age
        newest_dir = dir

    cd newest_dir

我尝试使用 cd $（find $ 1 / * -prune -type d 2> / dev / null | xargs stat -c％Y％n 2> / dev / null |排序-nr |头-n 1 |从 -to-newest-directory>此帖子，但是cd将我引导到计算机上的最新目录中。

I have tried using cd "$( find "$1"/* -prune -type d 2>/dev/null | xargs stat -c "%Y %n" 2>/dev/null | sort -nr | head -n 1 | cut -d " " -f 2-)" from this post, but that instead cd's me into the newest directory on my computer.

本意是用于目录

parent_dir:
  child_1 | Last Edited 1 Hr Ago
  child_2 | Last Edited 1 Yr Ago
  child_3 | Last Edited 2 Yr Ago
  child_4 | Last Edited 1 Min Ago
  child_5 | Last Edited 1 Week Ago

该命令将 cd 将我导入 child_4

推荐答案

您要使用的代码是旨在成为功能的主体；正确调用函数集 $ 1 。就其本身而言，可能未设置 $ 1 ，因此在 /上的查找运算符（与 / 相同），而不是 top_dir 。

The code you are trying to use is intended to be the body of a function; calling the function sets $1 properly. By itself, $1 probably isn't set, and so find operators on ""/ (same as /), not top_dir.

new_cd () {
  cd "$( find "$1"/* -prune -type d 2>/dev/null | xargs stat -c "%Y %n" 2>/dev/null | sort -nr | head -n 1 | cut -d " " -f 2-)"
}

new_cd top_dir

这可以简化一些。无需使用 find 或 xargs ；一个简单的循环就可以了。而且，既然您现在有了函数，就无需将所有内容都塞进一行。

This can be simplified a little. There's no need to use find or xargs; a simple loop will do. And since you have a function now, there's no need to cram everything in one line.

new_cd () {
  new_d=$(for d in "$1"/*/; do
      stat -c "%Y %n" "$d" 2> /dev/null
  done | sort -nr |
         head -n |
         cut -d " " -f 2-)
  cd "$new_d"
}

这有一个小缺点：命令替换将在 cut 的输出中吃掉所有尾随的换行符，因此请确保没有您的目录名称以换行符结尾。 （可以修复此极其微小的错误，但可能不值得这样做；仅需注意即可。）

This has one minor drawback: the command substitution will eat any trailing newlines in the output of cut, so make sure none of your directory names ends with a newline character. (This extremely minor bug can be fixed, but it probably isn't worth doing so; just be aware of it.)

它还有一个更大的缺点： em> non 跟踪的换行符没有被吃掉了，您不能假设循环的输出每行只包含一个文件。一个文件可以占用多行。最简单的解决方法是避免使用换行符的目录名称。

It also has a bigger drawback: since non-trailing newlines aren't eaten, you cannot assume the output of the loop consists of exactly one file per line; a single file could occupy multiple lines. The easiest fix is to avoid directory names with newlines. A more robust fix abandons the pipeline.

new_cd () {
  local newest_time newest_d
  for d in "$1"/*/; do
    t=$(stat -c "%Y" "$d")
    if (( t > newest_time )); then
      newest_time=$t
      newest_d=$d
    fi
  done
  cd "$newest_d"
}

这篇关于将Bash脚本cd到目录中的最新目录中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！