Django模板算术 [英] Django Template Arithmetic

问题描述

在我的模板中，我遍历一个列表，尝试进行两列布局。由于需要两列布局，因此我需要在for循环中编写的标记取决于 forloop.counter0 是偶数还是奇数。如果我具有使用模板语言编写的Python的全部功能，那么确定 forloop.counter0 的奇偶校验将是微不足道的，但不幸的是，并非如此。我如何使用Django模板语言测试 forloop.counter0 是偶数还是奇数，还是一样好，还有另一种方法可以使列表中的元素交替显示吗？

In my template, I am looping through a list, trying to make a two-column layout. Because of the desired two-column layout, the markup I need to write in the for loop is dependent on whether forloop.counter0 is even or odd. If I had the full power of Python in the template language, determining the parity of forloop.counter0 would be trivial, but unfortunately that is not the case. How can I test whether forloop.counter0 is even or odd using the Django template language, or just as good, is there another way I could get elements in the list to display alternatively in the left and right columns?

预先感谢！

推荐答案

您可以将 divisibleby 过滤器与<$ c $一起使用c> forloop.counter ：

{% if forloop.counter|divisibleby:"2" %}even{% else %}odd{% endif %}

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