Django 模板剥离空间? [英] Django templates stripping spaces?

问题描述

我在使用 Django 模板和 CharField 模型时遇到问题.

I'm having trouble with Django templates and CharField models.

所以我有一个带有 CharField 的模型，它创建了一个用下划线替换空格的 slug.如果我创建一个对象 Somename Somesurname，这会创建 slug Somename_Somesurname 并在模板上按预期显示.

So I have a model with a CharField that creates a slug that replaces spaces with underscores. If I create an object, Somename Somesurname, this creates slug Somename_Somesurname and gets displayed as expected on the template.

但是，如果我创建一个对象，Somename Somesurname(注意第二个空格)，将创建 slug Somename__Somesurname，尽管在​​ Django 控制台上我将其视为 ，在模板上显示为Somename Somesurname.

However, if I create an object, Somename Somesurname (notice the second space), slug Somename__Somesurname is created, and although on the Django console I see this as <Object: Somename Somesurname>, on the template it is displayed as Somename Somesurname.

那么 Django 模板会以某种方式去除空格吗?是否有过滤器可以用来获取带有空格的名称?

So do Django templates somehow strip spaces? Is there a filter I can use to get the name with its spaces?

推荐答案

让我先说@DNS 的答案是正确的，为什么没有显示空格.

Let me preface this by saying @DNS's answer is correct as to why the spaces are not showing.

考虑到这一点，此模板过滤器将用  

With that in mind, this template filter will replace any spaces in the string with  

用法:

{{ "hey there  world"|spacify }}

输出将是 hey there  world

代码如下:

from django.template import Library
from django.template.defaultfilters import stringfilter
from django.utils.html import conditional_escape
from django.utils.safestring import mark_safe
import re

register = Library()

@stringfilter
def spacify(value, autoescape=None):
    if autoescape:
    esc = conditional_escape
    else:
    esc = lambda x: x
    return mark_safe(re.sub('s', '&'+'nbsp;', esc(value)))
spacify.needs_autoescape = True
register.filter(spacify)

有关模板过滤器如何工作以及如何安装它们的说明，查看文档.

For notes on how template filters work and how to install them, check out the docs.

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