如何在python中将很长的字符串拆分为较短的字符串列表 [英] How do i split a very long string into a list of shorter strings in python

问题描述

在我当前的django项目中，我有一个模型，该模型存储非常长的字符串（每个DB条目可以为5000-10000甚至更多个字符），然后我需要在用户调用记录时拆分它们（它确实需要在数据库中的一条记录中）。我需要的是返回一个较短字符串（我返回的列表中每个字符串100-500个字符）的列表（queryset？取决于是否在 SQL部分或按原样获取所有列表并在视图中进行解析）。

In my current django project I have a model that stores very long strings (can be 5000-10000 or even more characters per DB entry) and then i need to split them when a user is calling the record (it really need to be in one record in the DB). What i need is it to return a list (queryset? depends if in the "SQL" part or getting all the list as is and doing the parsing in the view) of shorter strings (100 - 500 characters per sting in the list i return to the template).

我找不到任何地方的python split命令，示例或任何答案……。

I couldn't find anywhere a python split command nor example or any kind of answer for that....

我总是可以算单词和追加单词，但是算单词....但是我敢肯定，某种东西必须要有某种功能....

I could always count words and append but count words.... but i am sure there has to be some kind of function for that sort of things....

编辑：谢谢大家，但我想我听不懂，

thank you everyone, but i guess i wasn't understood,

示例：

Example:

字符串：这是一个很长的字符串，包含许多很多很多其他句子，没有一个字符可以用来分割，只是按单词数

The String: "This is a very long string with many many many many and many more sentences and there is not one character that i can use to split by, just by number of words"

字符串是Django模型的textField。

the string is a textField of django model.

我需要拆分它，说出每个 5个字，这样我就会得到：

i need to split it, lets say every 5 words so i will get:

[[这是一个很长的字符串，'有很多很多很多'，'还有很多句子，还有'，'没有一个字符'，'我可以使用到'，'由数字分隔'，'''''

问题是几乎每一个编程语言中，每词个数是一种工具功能，但我在python中找不到。

The thing is that is almost every programming languages there is split per number of words" kind of utility function but i can't find one in python.

谢谢，
Erez

thanks, Erez

推荐答案

>>> s = "This is a very long string with many many many many and many more sentences and there is not one character that i can use to split by, just by number of words"
>>> l = s.split()
>>> n = 5
>>> [' '.join(l[x:x+n]) for x in xrange(0, len(l), n)]
['This is a very long',
 'string with many many many',
 'many and many more sentences',
 'and there is not one',
 'character that i can use',
 'to split by, just by',
 'number of words']

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