如何在python中将字节字符串拆分为单独的字节 [英] How to split a byte string into separate bytes in python
问题描述
好的,所以我一直在使用 python 来尝试创建波形图像,我正在使用 song = wave.open()
.wav 文件从 .wav
文件中获取原始数据code> 和 song.readframes(1)
,返回:
b'\x00\x00\x00\x00\x00\x00'
我想知道的是如何将其拆分为三个单独的字节,例如b'\x00\x00'
, b'\x00\x00'
, b'\x00\x00'
因为每帧都是3个字节宽所以我需要每个单独字节的值才能形成波形.我相信无论如何我都需要这样做.
您可以对 byte
对象使用切片:
然而,在处理这些帧时,您可能还想了解 memoryview()
对象;这些让您可以将字节解释为 C 数据类型,而无需您进行任何额外的工作,只需在底层字节上投射视图"即可:
mv
对象现在是一个内存视图,将每 2 个字节解释为一个无符号短整型;所以它现在的长度为 3,每个索引都是一个整数值,基于底层字节.
Ok so I've been using python to try create a waveform image and I'm getting the raw data from the .wav
file using song = wave.open()
and song.readframes(1)
, which returns :
b'\x00\x00\x00\x00\x00\x00'
What I want to know is how I split this into three separate bytes, e.g. b'\x00\x00'
, b'\x00\x00'
, b'\x00\x00'
because each frame is 3 bytes wide so I need the value of each individual byte to be able to make a wave form. I believe that's how I need to do it anyway.
You can use slicing on byte
objects:
>>> value = b'\x00\x01\x00\x02\x00\x03'
>>> value[:2]
b'\x00\x01'
>>> value[2:4]
b'\x00\x02'
>>> value[-2:]
b'\x00\x03'
When handling these frames, however, you probably also want to know about memoryview()
objects; these let you interpret the bytes as C datatypes without any extra work on your part, simply by casting a 'view' on the underlying bytes:
>>> mv = memoryview(value).cast('H')
>>> mv[0], mv[1], mv[2]
256, 512, 768
The mv
object is now a memory view interpreting every 2 bytes as an unsigned short; so it now has length 3 and each index is an integer value, based on the underlying bytes.
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