django rest api用于提前搜索 [英] django rest api for advance search
问题描述
我想使用django rest框架创建一个api,它将进行一些高级搜索,例如将杂货项目列表保存在数据库中,并且用户要创建杂货列表,然后输入前2或3个字母然后我的api会查询以获取项目名称的其余部分,并向用户建议
i want to create a api using django rest framework which will do some advance search, say a list of grocery item is saved in database and user want to create a list of grocery and he enters first 2 or 3 letters and then my api will do query to get rest of the item name and will suggest to user
我已经看到了 drf干草堆,但不确定是否能满足我的要求。它还不支持Django LTS版本1.11。
I have seen the documentation of drf haystack but not sure whether will it fulfill my requirement. Also it does not support django LTS version 1.11 .
能否请您提出一些建议? django rest框架本身是否提供创建这种api的任何支持,该api会进行我上面提到的这种高级搜索
?我只是需要一些建议,因为我是django rest框架中的新手。
Can you please give me some suggestion? is django rest framework itself provide any support to create such a api which will do such advance search
which i mentioned above? i just need some suggestion as i am new in django rest framework.
推荐答案
如果您想使用建议进行搜索,则可以使用jquery自动完成输入并将其链接到生成杂货的视图,无需使用其余框架即可完成此简单任务。
if you want a search with suggestions you can use jquery autocomplete input and link it a view that generate the groceries, no need to use rest-framework for this simple task.
html代码:
<script>
$(function() {
$("#your_input_id").autocomplete({
source: "{% url 'url_name' %}",
minLength: 2,
});
});
</script>
让我们创建视图:
import json # or simplejson
def get_grocery(request):
if request.is_ajax():
q = request.GET.get('term', '')
places = Grocery.objects.filter(grocery_name__icontains=q)
results = []
for pl in places:
place_json = {}
place_json['id'] = pl.id
place_json['label'] = pl.grocery_name
place_json['value'] = pl.grocery_name
results.append(place_json)
data = json.dumps(results)
else:
data = 'fail'
mimetype = 'application/json'
return HttpResponse(data, mimetype)
最后输入网址:
url(r'^api/get_grocery/', views.get_grocery, name='url_name'),
不要忘记导入jqu ery
don't forget to import the jquery
<!-- jQuery !-->
<link rel="stylesheet" href="http://code.jquery.com/ui/1.8.18/themes/base/jquery-ui.css" type="text/css" media="all" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript">
</script> <script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.min.js" type="text/javascript"></script>
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