Django rest框架&外部API [英] Django rest framework & external api
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问题描述
我想从外部API( https://example.com/consumers )获取数据。我可以像这样构建urls.py吗?
i wanna get my data from an external API (https://example.com/consumers). Can I build my urls.py like this?
url(r'^(?P<test.com/consumers)>[0-9]+)$/', views.get, name="get"),
或者您还有其他人吗)好主意?
Or do you have any other(s) good idea(s) ?
谢谢。
推荐答案
我认为最好创建自己的url端点,该端点映射到向外部API发出请求的视图
I think it would be better to create your own url endpoint that maps to a view which makes a request to the external API.
# urls.py
url(r'^external-api/$', external_api_view)
# views.py
import requests
import time
from rest_framework import status
from rest_framework.response import Response
MAX_RETRIES = 5 # Arbitrary number of times we want to try
def external_api_view(request):
if request.method == "GET":
attempt_num = 0 # keep track of how many times we've retried
while attempt_num < MAX_RETRIES:
r = requests.get("https://example.com/consumers", timeout=10)
if r.status_code == 200:
data = r.json()
return Response(data, status=status.HTTP_200_OK)
else:
attempt_num += 1
# You can probably use a logger to log the error here
time.sleep(5) # Wait for 5 seconds before re-trying
return Response({"error": "Request failed"}, status=r.status_code)
else:
return Response({"error": "Method not allowed"}, status=status.HTTP_400_BAD_REQUEST)
仅例。您也可以将其作为基于类的视图来实现。
Just an example. You can do it as a class-based view as well.
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