将动态值传递给内置的Django url [英] Pass Dynamic Value to Django url built-in

问题描述

在一个视图中，我正在维护一个词典，该词典包含一些要显示在< a> 中的数据： //docs.djangoproject.com/zh-CN/2.1/ref/templates/builtins/#url rel = nofollow noreferrer>内置Django url 内置。

my_view.py

 链接= [
 {
'name'：'link 1'，
'pattern'：'fe：upload'
}，
 {
'name '：'链接2'，
'模式'：'fe：download'
} 
] 
  

它将像这样硬编码：

 < a href = {％url' fe：upload'id％}> up< / a> 
< a href = {％url’fe：download’id％}> down< / a> 
  

但是我一直在努力使其陷入困境

my_template.html

 < ul> 
 {％for link in links％} 
< li> 
< a href =’{％url link.pattern id％}'> {{link.name}}< / a> 
< / li> 
 {％endfor％} 
< / ul> 
  

我尝试过：

• 使用 \ 和HTML实体
将引号转义

• 将href放入临时变量，例如： {％with href = url'link.pattern'％} 并收到错误：

< blockquote>

u'with'收到了无效的令牌：u'link.pattern'

如何在此循环中添加动态模式以生成锚点？

解决方案

您是否尝试过以下操作：

  {％，link.pattern为link_pattern％} 
< li> 
< a href =’{％url link_pattern id％}'> {{link.name}}< / a> 
< / li> 
 {％结尾％} 
  

Within a view, I am maintaining a dictionary containing some data I would like to display in an <a> in a template with the Django url built-in.

my_view.py

links = [
  {
    'name': 'link 1',
    'pattern': 'fe:upload'
  },
  {
    'name': 'link 2',
    'pattern': 'fe:download'
  }
]

It will work hardcoded like this:

<a href="{% url 'fe:upload' id %}">up</a>
<a href="{% url 'fe:download' id %}">down</a>

However I'm struggling to put it into a loop

my_template.html

<ul>
  {% for link in links %}
    <li>
      <a href='{% url link.pattern id %}'>{{link.name}}</a>
    </li>
  {% endfor %}
</ul>

I have tried:

• escaping the quotations with \ and HTML entities
• putting the href into a temp variable, eg: {% with href=url 'link.pattern' %} and get the error:

u'with' received an invalid token: u"'link.pattern'"

how can I put a dynamic pattern into this loop to generate an anchor?

解决方案

Have you tried the following:

{% with link.pattern as link_pattern %}
    <li>
      <a href='{% url link_pattern id %}'>{{link.name}}</a>
    </li>
{% endwith %}

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