使用Docker进行继承或嵌套 [英] Inheritance or nesting with docker compose

问题描述

启动应用程序的最佳方法是使用我们提供的docker compose。 docker-compose 以正确的配置启动所有服务。

The best way to start our application is by using a docker compose we provide. The docker-compose starts all the services with the right configuration.

现在，我们想提供一个 docker-commit 应用程序在不同的后端运行。在这个组合中，有8个10服务是相同的，而2个是不同的。

Now we would like to provide a docker-compose where the application runs with a different backend. In this compose 8 out 10 services are the same and 2 are different.

如何在不重复代码的情况下实现这一目标？
我看到服务可以从另一个docker-compose文件扩展服务，但是仍然需要列出两个文件中的所有10个服务。

How to achieve this without code duplication? I see that a service can extend a service from another docker-compose file, however this would still require to list all the 10 services in both files.

推荐答案

使用docker-compose 1.6，应该可以实现。

With docker-compose 1.6 this should be possible.

创建 docker-compose.yml 与您的常用服务：

service01:
  image: image01
  links:
    - service02

service02:
  image: image02

第二个文件， docker-compose.prod.yml 与您的独特服务：

And a second file, docker-compose.prod.yml with your unique services:

service03:
  image: image03
  links:
    - service02

现在，您可以使用以下命令启动服务01、02和03：

Now you can start service 01, 02 and 03 with this command:

docker-compose -f docker-compose.yml -f docker-compose.prod.yml

有关更多信息，请参见官方文档：
< a href = https://docs.docker.com/compose/extends/#multiple-compose-files rel = noreferrer> https://docs.docker.com/compose/extends/#multiple-compose-文件

For more information, see the official documentation: https://docs.docker.com/compose/extends/#multiple-compose-files

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