如何在Symfony4中将参数传递给自定义的教义类型 [英] How to pass parameters to a custom Doctrine type in Symfony4

问题描述

我开发了一种新的Doctrine类型来加密字符串。

I have developed a new Doctrine type to encrypt strings.

<?php
namespace App\Doctrine\DBAL\Types;

use Doctrine\DBAL\Platforms\AbstractPlatform;
use Doctrine\DBAL\Types\StringType;
use App\Security\Encoder\OpenSslEncoder;

class EncryptedStringType extends StringType {

    const MTYPE = 'encrypted_string';

    private $cypherMethod;
    private $iv;
    private $privateKey;

    public function convertToPHPValue($value, AbstractPlatform $platform)
    {
        $openSslEncoder = new OpenSslEncoder($this->cypherMethod, $this->iv, $this->privateKey);

        return $openSslEncoder->decrypt($value);
    }

    public function convertToDatabaseValue($value, AbstractPlatform $platform)
    {
        $openSslEncoder = new OpenSslEncoder($this->cypherMethod, $this->iv, $this->privateKey);

        return $openSslEncoder->encrypt($value);
    }

    public function getName()
    {
        return self::MTYPE;
    }

    /**
     * @param mixed $cypherMethod
     */
    public function setCypherMethod($cypherMethod)
    {
        $this->cypherMethod = $cypherMethod;
    }

    /**
     * @param mixed $iv
     */
    public function setIv($iv)
    {
        $this->iv = $iv;
    }

    /**
     * @param mixed $privateKey
     */
    public function setPrivateKey($privateKey)
    {
        $this->privateKey = $privateKey;
    }
} 

在旧的Symfony3应用程序中，我注册了新类型

In the old Symfony3 applications, I registered the new type in the following way:

<?php

namespace AppBundle;

use Symfony\Component\HttpKernel\Bundle\Bundle;
use Doctrine\DBAL\Types\Type;

class AppBundle extends Bundle
{
    public function __construct()
    {
        Type::addType('encrypted_string', 'AppBundle\Doctrine\DBAL\Types\EncryptedStringType');
    }

    public function boot()
    {
        $encryptedString = Type::getType('encrypted_string');
        $encryptedString->setCypherMethod($this->container->getParameter('open_ssl_cypher_method'));
        $encryptedString->setIv($this->container->getParameter('open_ssl_iv'));
        $encryptedString->setPrivateKey($this->container->getParameter('open_ssl_private_key'));
    }
}

我如何在新的Symfony4应用程序中执行相同的操作？我知道我可以在doctrine.yaml配置文件中注册一种新类型。但是我需要设置密码参数...如何在新版本中设置对象参数？

How I can do the same in the new Symfony4 applications? I know that I can register a new type in the doctrine.yaml config file. But I need to set the cypher parameters... How I can set the object parameters in the new version?

非常感谢。

推荐答案

Symfony 4 内核类具有 boot（）方法，其用途类似，因此可以确保将代码在那里移动：

In the same way, Symfony 4 Kernel class has a boot() method with similar purpose, so you can move that code there for sure:

// src/Kernel.php

class Kernel extends BaseKernel
{   
    // ...

    public function boot()
    {
        parent::boot();

        // move here.
    }

// ...

这篇关于如何在Symfony4中将参数传递给自定义的教义类型的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！