改编类使用php的__call方法：传递参数 [英] Adapting a class Using php's __call method: Passing the parameters

问题描述

基于我的Symfony 3.4项目中的 answer ，我想到了使用魔术 __ call 方法，以便有一种通用的方式来调用存储库即服务：

Based upon answer on my Symfony 3.4 project I thought of using the magic __call method in order to have a common way to invoke repositories as a service:

namespace AppBundle\Services;

use Doctrine\ORM\EntityManagerInterface;

class RepositoryServiceAdapter
{
        private $repository=null;

        /**
        * @param EntityManagerInterface the Doctrine entity Manager
        * @param String $entityName The name of the entity that we will retrieve the repository
        */
        public function __construct(EntityManagerInterface $entityManager,$entityName)
        {
            $this->repository=$entityManager->getRepository($entityName)
        }

        public function __call($name,$arguments)
        {     
          if(empty($arguments)){ //No arguments has been passed
             $this->repository->$name();
          } else {
             //@todo: figure out how to pass the parameters
             $this->repository->$name();
          }
        }
}

问题：

存储库方法将具有以下形式：

A repository method will have this form:

public function aMethod($param1,$param2)
{
  //Some magic is done here
}

因此，如果我确切知道哪种方法，我将需要某种方式迭代数组 $ arguments 以便将参数传递给函数调用我会任意传递参数，例如，如果我知道一个方法有3个参数，我将使用该参数：

So I will need somehow to iterate the array $arguments in order to pass the parameters to the function if I knew exactly what method would be called I would arbitatily pass the parameters, for example if I knew that a method had 3 parameters I would use:

        public function __call($name,$arguments)
        {
           $this->repository->$name($argument[0],$argument[1],$argument[2]);
        }

但这对我来说似乎不切实际，也不是一个具体的解决方案，因为方法可以超过1个参数。我想我需要解决以下问题：

But that seems impractical and not a concrete solution for me because a method can have more than 1 parameters. I think I need to solve the following problems:

1. 我将如何找出一个方法有多少个参数？


2. 如何在迭代数组 $ arguments 时传递参数？

1. How I will find out how many parameters a method has?
2. How to pass the arguments while iterating the array $arguments?

推荐答案

从PHP 5.6开始，您具有参数解压缩，它使您可以完全使用 ... 之后执行操作，因此

As of PHP 5.6 you have argument unpacking which allows you to do exactly what your after using ..., so

$this->repository->$name($argument[0],$argument[1],$argument[2]);

成为...

$this->repository->$name(...$argument);

这将传递任何数字或参数，就像它们是单个字段一样。

This will pass any number or arguments as though they are individual fields.

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