PHP DOM:获取不包含子节点的NodeValue [英] PHP DOM: Get NodeValue excluding the child nodes
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问题描述
我有一个变量 $ content
,其中包含一段HTML代码:
I have a variable$content
containing a piece of HTML code :
<b>AMZN 466.00 ( 15743 ) ( <span class='red'> -1 </span>)
MSFT 290.00 ( 37296 ) ( <span class='red'> -2 </span>)
TWTR 4,000.00 ( 20 ) ( <span class=''> 0 </span>)</b>
现在,我想要< b> $的值c $ c>使用PHP DOM排除
< span>
的值。如何才能做到这一点?
Now, I want the values of <b>
excluding the values of <span>
using PHP DOM. How can this be done? A code snippet would be helpful.
到目前为止,我已经尝试过:
So far, I've tried this:
$dom = new domDocument;
@$dom->loadHTML($content);
$contents_i_want = $dom->getElementsByTagName('b');
foreach($contents_i_want as $content_i_want){
$filtered_content = $content_i_want->nodeValue;
echo $filtered_content;
}
推荐答案
希望这对您有所帮助..
Hope this will help you out..
<?php
ini_set('display_errors', 1);
$string='<html><body><b>AMZN 466.00 ( 15743 ) ( <span class=\'red\'> -1 </span>)
MSFT 290.00 ( 37296 ) ( <span class=\'red\'> -2 </span>)
TWTR 4,000.00 ( 20 ) ( <span class=\'\'> 0 </span>)</b></body></html>';
$dom = new DOMDocument();
$dom->loadHTML($string);
$dom->getElementsByTagName("b");
$xpath= new DOMXPath($dom);
$result=$xpath->query("//b/span");//here we are querying domdocument to find span which is inside b.
$nodesToRemove=array();//here we are maintaining an array of nodes which we want to remove
foreach($result as $node)
{
$node->parentNode->removeChild($node);//removing nodes from its parent
}
echo $dom->getElementsByTagName("b")->item(0)->textContent;//displaying content after removing nodes.
输出:
AMZN 466.00 ( 15743 ) ( )
MSFT 290.00 ( 37296 ) ( )
TWTR 4,000.00 ( 20 ) ( )
这篇关于PHP DOM:获取不包含子节点的NodeValue的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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