PHP DOM - 计数子节点? [英] PHP DOM - counting child nodes?
本文介绍了PHP DOM - 计数子节点?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
HTML片段#1
<div>
</div>
<div>
<h1>headline</h1>
</div>
HTML片段#2
<div></div>
<div><h1>headline</h1></div>
PHP代码
$doc = new DOMDocument();
$doc->loadHTML($x);
$xpath = new DOMXpath($doc);
$divs = $xpath->query("//div");
foreach ($divs as $div) echo $div->childNodes->length,"<br />";
输出与 $ x =
片段#1
1
3
Output with $x =
snippet #1
1
3
输出与 $ x =
片段#2
0
1
Output with $x =
snippet #2
0
1
查看工作演示: http://codepad.viper-7.com/11BGge
我的问题
1.怎么可能?
2.如何正确使用 DOM
?
编辑:
作为Silkfire说,空格是考虑了一个文本节点。我设置
EDIT:
as Silkfire said, empty space is considered a text node. I set
$doc->preserveWhiteSpace = false;
但结果仍然相同: http://codepad.viper-7.com/bnG5io
任何想法?
推荐答案
只需计算循环中的非文本节点:
Just count non-text nodes in your loop:
$count = 0;
foreach($div->childNodes as $node)
if(!($node instanceof \DomText))
$count++;
print $count;
使用xpath:
Using xpath:
$nodesFromDiv1 = $xpath->query("//div[1]/*")->length;
$nodesFromDiv2 = $xpath->query("//div[2]/*")->length;
要删除空文本节点,当 preserveWhiteSpace = false
不工作(正如我在聊天中建议的):
To remove empty text nodes, when preserveWhiteSpace=false
is not working (as I suggested in the chat):
$textNodes = $xpath->query('//text()');
foreach($textNodes as $node)
if(trim($node->wholeText) === '')
$node->parentNode->removeChild($node);
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