检索PHP中的相对DOM节点 [英] Retrieving relative DOM nodes in PHP
问题描述
我想检索文档中下一个元素标签的数据，例如：
I want to retrieve the data of the next element tag in a document, for example:
我想检索< blockquote> ;内容1< / blockquote> 仅适用于每个不同的跨度。
I would like to retrieve <blockquote> Content 1 </blockquote> for every different span only.
<html>
<body>
<span id=12341></span>
<blockquote>Content 1</blockquote>
<blockquote>Content 2</blockquote>
<!-- misc html in between including other spans w/ no relative blockquotes-->
<span id=12342></span>
<blockquote>Content 1</blockquote>
<!-- misc html in between including other spans w/ no relative blockquotes-->
<span id=12343></span>
<blockquote>Content 1</blockquote>
<blockquote>Content 2</blockquote>
<blockquote>Content 3</blockquote>
<blockquote>Content 4</blockquote>
<!-- misc html in between including other spans w/ no relative blockquotes-->
<span id=12344></span>
<blockquote>Content 1</blockquote>
<blockquote>Content 2</blockquote>
<blockquote>Content 3</blockquote>
</body>
</html>
现在我想知道两件事：
1。）我如何编写一个匹配的表达式，仅输出封闭元素（< span>< / span> ）之后紧随其后的块引用？
1.)How can I write an expression that matches and only outputs a blockquote that's followed right after a closed element (<span></span>)?
2。）如果我想要的话，如果我将来有需要在仍适用于
2.)If I wanted, how could I get Content 2, Content 3, etc if I ever have a need to output them in the future while still applying to the rules of the previous question?
推荐答案
现在我想知道两件事：
Now two things I'm wondering:
1。）如何编写匹配的表达式，仅输出封闭的
元素后紧跟的块引用
（< ; span>< / span> ）？
1.)How can I write an expression that matches and only outputs a blockquote
that's followed right after a closed
element (<span></span>)?
假定所提供的文本已转换到格式正确的XML文档（您需要将 id 属性的值括在引号中）
Assuming that the provided text is converted to a well-formed XML document (you need to enclose the values of the id attributes in quotes)
使用：
/*/*/span/following-sibling::*[1][self::blockquote]
此用英语表示：全选 blockquote 每个元素都是第一个直接的 span 元素是文档顶部元素的孙子。
This means in English: Select all blockquote elements each of which is the first, immediate following sibling of a span element that is a grand-child of the top element of the document.
2。）如果我愿意，如果我曾经在
的将来需要输出
，如何获得Content 2，Content 3等。同时仍适用于上一个问题的
规则？
2.)If I wanted, how could I get Content 2, Content 3, etc if I ever have a need to output them in the future while still applying to the rules of the previous question?
是。
在 span <之后，您可以获得所有连续的 blockquote 元素集/ code>：
You can get all sets of contigious blockquote elements following a span:
/*/*/span/following-sibling::blockquote
[preceding-sibling::*[not(self::blockquote)][1][self::span]]
在（N + 1）-st 跨度之后，您可以获得连续的由： blockquote 元素集
/*/*/span/following-sibling::blockquote
[preceding-sibling::*
[not(self::blockquote)][1]
[self::span and count(preceding-sibling::span)=$vN]
]
其中 $ vN 应为
因此，在第一个之后紧接的 blockquote 元素集 span 由选择：
Thus, the set of contigious set of blockquote elements following the first span is selected by:
/*/*/span/following-sibling::blockquote
[preceding-sibling::*
[not(self::blockquote)][1]
[self::span and count(preceding-sibling::span)=0]
]
一组连续的 blockquote集在第二个选择：跨度中的元素由
/*/*/span/following-sibling::blockquote
[preceding-sibling::*
[not(self::blockquote)][1]
[self::span and count(preceding-sibling::span)=1]
]
等。 ...
请参见 XPath Visualizer 由以下表达式选择的节点：
See in the XPath Visualizer the nodes selected by the following expression :
/*/*/span/following-sibling::blockquote
[preceding-sibling::*
[not(self::blockquote)][1]
[self::span and count(preceding-sibling::span)=3]
]
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