Java:检查两个双精度值是否匹配特定的小数位数 [英] Java: Check if two double values match on specific no of decimal places
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问题描述
比较这两个值将得出 true:
Comparing those two values shall result in a "true":
53.9173333333333 53.9173
推荐答案
如果要 a = 1.00001
并 b = 0.99999
被标识为相等:
If you want a = 1.00001
and b = 0.99999
be identified as equal:
return Math.abs(a - b) < 1e-4;
否则,如果要 a = 1.00010
和 b = 1.00019
被确定为相等,并且 a
和 b
是正数,不是正数:
Otherwise, if you want a = 1.00010
and b = 1.00019
be identified as equal, and both a
and b
are positive and not huge:
return Math.floor(a * 10000) == Math.floor(b * 10000);
// compare by == is fine here because both sides are integral values.
// double can represent integral values below 2**53 exactly.
否则,使用 truncate
方法,如图所示在中是否有任何函数可以在Java中截断double? :
Otherwise, use the truncate
method as shown in Are there any functions for truncating a double in java?:
BigDecimal aa = new BigDecimal(a);
BigDecimal bb = new BigDecimal(b);
aa = aa.setScale(4, BigDecimal.ROUND_DOWN);
bb = bb.setScale(4, BigDecimal.ROUND_DOWN);
return aa.equals(bb);
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