JAXB解组@XmlAnyElement [英] JAXB Unmarshalling @XmlAnyElement

问题描述

我创建了三个JAXB类： Home，Person，Animal 。 Java类
主页具有变量 List< Object>任何可能包含Person和/或Animal实例的。

I have created three JAXB class : Home , Person , Animal . Java Class Home have variable List<Object> any that may contain Person and/or Animal instance .

    public class Home {
        @XmlAnyElement(lax = true)
        protected List<Object> any;
    //setter getter also implemented
    }
@XmlRootElement(name = "Person")                            // Edited
    public class Person {
        protected String name; //setter getter also implemented
     } 
@XmlRootElement(name = "Animal")                             // Edited
    public class Animal {
       protected String name; //setter getter also implemented
     }

---

/ * 解组后 * /

 Home home ;

                for(Object obj : home .getAny()){
                    if(obj instanceof Person ){
                        Person  person = (Person )obj;
                        // .........
                    }else if(obj instanceof Animal ){
                        Animal animal = (Animal )obj;
                        // .........
                    }
                }

我需要实现保存在 Home.any List 变量中的 Person或Animal 对象，但内容 Home.any列表是 com.sun.org.apache.xerces.internal.dom.ElementNSImpl 的实例而不是动物或人。

I need to achieve Person or Animal object saved in "Home.any" List variable but content of "Home.any" List is instance of com.sun.org.apache.xerces.internal.dom.ElementNSImpl instead of Animal or Person .

那么有没有办法实现动物或人实例，该实例保存在 Home.any列表中。

So is there a way to achieve Animal or Person instance that is saved in xml in "Home.any" List.

推荐答案

您需要在要显示为用<$ c $注释的字段/属性中作为实例的类上添加 @XmlRootElement c> @XmlAnyElement（lax = true）。

You need to add @XmlRootElement on the classes you want to appear as instances in the field/property you have annotated with @XmlAnyElement(lax=true).

首页

import java.util.List;
import javax.xml.bind.annotation.*;

@XmlAccessorType(XmlAccessType.FIELD)
public class Home {
    @XmlAnyElement(lax = true)
    protected List<Object> any;

    //setter getter also implemented
}

人员

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="Person")
public class Person {

}

动物

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="Animal")
public class Animal {

}

演示代码

input.xml

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <Person/>
    <Animal/>
    <Person/>
</root>

演示

import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;

public class Demo {

    public static void main(String[] args) throws JAXBException {
        JAXBContext jc = JAXBContext.newInstance(Home.class, Person.class, Animal.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        StreamSource xml = new StreamSource("src/forum20329510/input.xml");
        Home home = unmarshaller.unmarshal(xml, Home.class).getValue();

        for(Object object : home.any) {
            System.out.println(object.getClass());
        }
    }

}

输出

class forum20329510.Person
class forum20329510.Animal
class forum20329510.Person

更多信息

• http://blog.bdoughan.com/2012/12 /jaxbs-xmlanyelementlaxtrue-explained.html



For More Information

• http://blog.bdoughan.com/2012/12/jaxbs-xmlanyelementlaxtrue-explained.html

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