JAXB中的解组错误 [英] Unmarshal error in JAXB
问题描述
这是PersonType类的生成代码。
package demo;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType（XmlAccessType.FIELD）
@XmlType（name =PersonType，propOrder = {
name，
address
}）
公共类PersonType {
@XmlElement（name =Name，required = true）
protected String name;
@XmlElement（name =Address，required = true）
protected List< AddressType>地址;
public String getName（）{
return name;
}
public void setName（String value）{
this.name = value;
}
公开列表< AddressType> getAddress（）{
if（address == null）{
address = new ArrayList< AddressType>（）;
}
返回this.address;
}
}
这是生成的代码 AddressTypeclass。
package demo;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlSchemaType;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType（XmlAccessType.FIELD）
@XmlType（name =AddressType，propOrder = {
number，
street
}）
公共类AddressType {
@XmlElement（name =Number）
@XmlSchemaType（name =unsignedInt）
protected long number;
@XmlElement（name =Street，required = true）
protected String street;
public long getNumber（）{
返回号码;
}
public void setNumber（long value）{
this.number = value;
}
public String getStreet（）{
return street;
}
public void setStreet（String value）{
this.street = value;
}
}
这是我想要的xml文件unmarshal
< Person xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
xsi：noNamespaceSchemaLocation =C：\ JAXB Demo\demo.xsd>
< Name> Sharon Krisher< / Name>
<地址>
< Street> Iben Gevirol< / Street>
< Number> 57< / Number>
< /地址>
<地址>
< Street> Moshe Sharet< / Street>
< Number> 89< / Number>
< /地址>
< / Person>
代码foe unarchall
JAXBContext context = JAXBContext.newInstance（PersonType.class）;
Unmarshaller unmarshaller = context.createUnmarshaller（）;
//unmarshaller.setValidating(true）;
PersonType person =（PersonType）unmarshaller.unmarshal（new File（C：\\Users\\sithi\\workspace \\TestJAXB \\src\\ data .xml））;
此代码给出了一个例外：
线程main中的异常javax.xml.bind.UnmarshalException：意外元素（uri：，local：PersonType）。预期元素是（无）
有两种方法可以将类与根元素相关联。第一个是类上的 @XmlRootElement ，第二个是用<$ c注释的类上的 @XmlElementDecl 注释$ c> @XmlRegistry （当从XML生成模型时，这个类被称为 ObjectFactory 。
创建 JAXBContext
生成模型时从XML Schema中你应该在包名上创建 JAXBContext ：
JAXBContext jc = JAXBContext.newInstance（demo）;
或生成 ObjectFactory class：
JAXBContext jc = JAXBContext.newInstance（demo.ObjectFactory.class）;
这将确保处理 ObjectFactory 类。 / p>
否 @XmlRootElement 或 @XmlElementDecl ？
如果没有 @XmlRootElement 或 @XmlElementDecl 将一个类与文档的根元素相关联，那么你将需要使用一个带有类参数的unmarshal方法。
PersonType pt = unmarshaller.unmarshal（xml，PersonType.class）。getValue（）;
This is the generated code for "PersonType" class.
package demo;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "PersonType", propOrder = {
"name",
"address"
})
public class PersonType {
@XmlElement(name = "Name", required = true)
protected String name;
@XmlElement(name = "Address", required = true)
protected List<AddressType> address;
public String getName() {
return name;
}
public void setName(String value) {
this.name = value;
}
public List<AddressType> getAddress() {
if (address == null) {
address = new ArrayList<AddressType>();
}
return this.address;
}
}
This is the generated code for "AddressType" class.
package demo;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlSchemaType;
import javax.xml.bind.annotation.XmlType;
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "AddressType", propOrder = {
"number",
"street"
})
public class AddressType {
@XmlElement(name = "Number")
@XmlSchemaType(name = "unsignedInt")
protected long number;
@XmlElement(name = "Street", required = true)
protected String street;
public long getNumber() {
return number;
}
public void setNumber(long value) {
this.number = value;
}
public String getStreet() {
return street;
}
public void setStreet(String value) {
this.street = value;
}
}
This is the xml file I want to unmarshal
<Person xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="C:\JAXB Demo\demo.xsd">
<Name>Sharon Krisher</Name>
<Address>
<Street>Iben Gevirol</Street>
<Number>57</Number>
</Address>
<Address>
<Street>Moshe Sharet</Street>
<Number>89</Number>
</Address>
</Person>
Code foe unarchall
JAXBContext context = JAXBContext.newInstance(PersonType.class);
Unmarshaller unmarshaller =context.createUnmarshaller();
//unmarshaller.setValidating(true);
PersonType person =(PersonType) unmarshaller.unmarshal(new File("C:\\Users\\sithi\\workspace\\TestJAXB\\src\\data.xml") );
This code gives an exception:
Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"PersonType"). Expected elements are (none)
There are two ways to associate a class with a root element. The first is @XmlRootElement on the class, the second is an @XmlElementDecl annotation on a class annotated with @XmlRegistry (when the model is generated from an XML a Schema this class is called ObjectFactory.
Creating the JAXBContext
When you generate a model from XML Schema you should create the JAXBContext on the package name:
JAXBContext jc = JAXBContext.newInstance("demo");
Or generated ObjectFactory class:
JAXBContext jc = JAXBContext.newInstance(demo.ObjectFactory.class);
This will make sure the ObjectFactory class is processed.
No @XmlRootElement or @XmlElementDecl?
If there isn't an @XmlRootElement or @XmlElementDecl associating a class with the root element of your document then you will need to use one of the unmarshal methods that take a class parameter.
PersonType pt = unmarshaller.unmarshal(xml, PersonType.class).getValue();
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