如何从根为xmlns的XML文件中获取数据 [英] How to get data from an XML file with xmlns in root

问题描述

number.xml

number.xml

<?xml version="1.0" encoding="utf-8"?>
<ResponseSent>
  <ResponseDate xmlns="http://example.com/schema">
   <emailid>[e-mail]</emailid>
    <number>22</number>
    <sent>2017-12-05</sent>
 </ResponseDate>

number.py

number.py

import xml.etree.ElementTree as ET
tree = ET.parse('number.xml')
root = tree.getroot()
for country in root.findall('ResponseDate'):
    rank = country.find('emailid').text
    name = country.find('number').text
    print(name, rank)

返回空结果，但是当我将xml修改为name =而不是xmlns =即可正常工作。但是，如何使该脚本与xmlns一起使用？？

Returning empty results, but when I modify the xml to name= instead of xmlns= then it is working. But, how to make this script work with the xmlns.?

推荐答案

请注意 xmlns 声明了默认名称空间，而没有前缀的后代元素从祖先隐式继承了默认名称空间。现在要在命名空间中查找元素，您可以
定义一个引用命名空间URI的前缀，并使用该前缀和目标元素的本地名称的组合：

Notice that xmlns without prefix in XML declares default namespace, and descendants element without prefix inherit default namespace from ancestor implicitly. Now to find element in namespace you can define a prefix that references the namespace URI, and use combination of that prefix and target element's local name :

....
ns = { 'd': 'http://example.com/schema' }
for country in root.findall('d:ResponseDate', ns):
    rank = country.find('d:emailid', ns).text
    name = country.find('d:number', ns).text
    print(name, rank)

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