根据RFC5322和https://en.wikipedia.org/wiki/Email_address的电子邮件ID验证 [英] Email Id validation according to RFC5322 and https://en.wikipedia.org/wiki/Email_address

问题描述

根据 RFC5322 并遵循

https://en.wikipedia.org/wiki/Email_address

下面是使用Java的示例代码

Below is the sample code using java and a regular expression to validate E-mail Ids.

public void checkValid() {
    List<String> emails = new ArrayList();
    //Valid Email Ids
    emails.add("[e-mail]");
    emails.add("[e-mail]");                   
    emails.add("[e-mail]");
    emails.add("[e-mail]");
    emails.add("[e-mail]");
    emails.add("[e-mail]");
    emails.add("[e-mail]");
    emails.add("[e-mail]");
    emails.add("carlosd'[e-mail]");
    emails.add("[e-mail]");
    emails.add("admin@mailserver1");
    emails.add("[e-mail]");
    emails.add("\" \"@example.org");
    emails.add("\"john..doe\"@example.org");

    //Invalid emails Ids
    emails.add("Abc.example.com");
    emails.add("A@b@[e-mail]");
    emails.add("a\"b(c)d,e:f;g<h>i[j\\k][e-mail]");
    emails.add("just\"not\"[e-mail]");
    emails.add("this is\"not\\[e-mail]");
    emails.add("this\\ still\"not\\[e-mail]");
                    emails.add("12[e-mail]");
    emails.add("[e-mail]");
    emails.add("john.doe@example..com");

    String regex = "^[a-zA-Z0-9_!#$%&'*+/=? \\\"`{|}~^.-]+@[a-zA-Z0-9.-]+$";

    Pattern pattern = Pattern.compile(regex);
    int i=0;
    for(String email : emails){
        Matcher matcher = pattern.matcher(email);
        System.out.println(++i +"."+email +" : "+ matcher.matches());
    }
}

实际输出：

   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   [e-mail] : true
   9.carlosd'[e-mail] : true
   [e-mail] : true
   11.admin@mailserver1 : true
   [e-mail] : true
   13." "@example.org : true
   14."john..doe"@example.org : true
   15.Abc.example.com : false
   16.A@b@[e-mail] : false
   17.a"b(c)d,e:f;g<h>i[j\k][e-mail] : false
   18.just"not"[e-mail] : true
   19.this is"not\[e-mail] : false
   20.this\ still"not\[e-mail] : false
   21.12[e-mail]    : true
   [e-mail] : true
   23.john.doe@example..com : true

预期输出：

[e-mail] : true
[e-mail] : true
[e-mail] : true
[e-mail] : true
[e-mail] : true
[e-mail] : true
[e-mail] : true
[e-mail] : true
9.carlosd'[e-mail] : true
[e-mail] : true
11.admin@mailserver1 : true
[e-mail] : true
13." "@example.org : true
14."john..doe"@example.org : true
15.Abc.example.com : false
16.A@b@[e-mail] : false
17.a"b(c)d,e:f;g<h>i[j\k][e-mail] : false
18.just"not"[e-mail] : false
19.this is"not\[e-mail] : false
20.this\ still"not\[e-mail] : false
21.12[e-mail] : false
[e-mail] : false
23.john.doe@example..com : false

如何更改我的正则表达式，以使以下电子邮件ID模式无效。

How can I change my regular expression so that it will invalidate the below patterns of email ids.

12[e-mail]
[e-mail]
john.doe@example..com 
just"not"[e-mail]

以下是正则表达式的标准：

Below are the criteria for regular expression:

本地部分

电子邮件的本地部分地址可以使用以下任何ASCII字符：

The local-part of the email address may use any of these ASCII characters:

1. 大写和小写拉丁字母 A到Z 和 a到z ;


2. 数字 0到9 ;


3. 特殊字符！＃$％&'* +-/ =？^ _`{|}〜


4. 点 。，条件是除非加引号
   ，否则不是第一个或最后一个字符，并且除非加引号，否则它不会连续出现
   （例如不允许 John..Doe @ example.com ，但
   John..Doe @ example.com ）；


5. 空格和（），：;<&@@ [ \] 字符，但有限制
   （它们只能在带引号的字符串内使用，如下面的
   段落所述，此外，反斜杠或双引号必须在
   之前加上反斜杠）；在本地部分的任一端都可以在括号中加上括号
   ；例如
   john.smith（comment）@example。 com 和
   （评论）[e-mail] 都等同于
   [e-mail] 。

1. uppercase and lowercase Latin letters A to Z and a to z;
2. digits 0 to 9;
3. special characters !#$%&'*+-/=?^_`{|}~
4. dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g. [e-mail] is not allowed but "John..Doe"@example.com is allowed);
5. space and "(),:;<>@[\] characters are allowed with restrictions (they are only allowed inside a quoted string, as described in the paragraph below, and in addition, a backslash or double-quote must be preceded by a backslash); comments are allowed with parentheses at either end of the local-part; e.g. john.smith(comment)@example.com and (comment)[e-mail] are both equivalent to [e-mail].

域

1. 大写和小写拉丁字母 A到Z 和 a到z ;


2. 位数 0到9 ，前提是顶级域名不是
   全部-numeric;


3. 连字符-，只要它不是第一个或最后一个ch拖拉机。
   在域以及本地部分都允许注释；例如
   ， john.smith @（comment）example.com 和
   [e-mail]（comment ）等同于
   [e-mail] 。

1. uppercase and lowercase Latin letters A to Z and a to z;
2. digits 0 to 9, provided that top-level domain names are not all-numeric;
3. hyphen -, provided that it is not the first or last character. Comments are allowed in the domain as well as in the local-part; for example, john.smith@(comment)example.com and [e-mail](comment) are equivalent to [e-mail].

推荐答案

您可以像这样 RFC5322

（参考正则表达式已修改）

"(?im)^(?=.{1,64}@)(?:(\"[^\"\\\\]*(?:\\\\.[^\"\\\\]*)*\"@)|((?:[0-9a-z](?:\\.(?!\\.)|[-!#\\$%&'\\*\\+/=\\?\\^`\\{\\}\\|~\\w])*)?[0-9a-z]@))(?=.{1,255}$)(?:(\\[(?:\\d{1,3}\\.){3}\\d{1,3}\\])|((?:(?=.{1,63}\\.)[0-9a-z][-\\w]*[0-9a-z]*\\.)+[a-z0-9][\\-a-z0-9]{0,22}[a-z0-9])|((?=.{1,63}$)[0-9a-z][-\\w]*))$"  

https://regex101.com/r/ObS3QZ/1

 # (?im)^(?=.{1,64}@)(?:("[^"\\]*(?:\\.[^"\\]*)*"@)|((?:[0-9a-z](?:\.(?!\.)|[-!#\$%&'\*\+/=\?\^`\{\}\|~\w])*)?[0-9a-z]@))(?=.{1,255}$)(?:(\[(?:\d{1,3}\.){3}\d{1,3}\])|((?:(?=.{1,63}\.)[0-9a-z][-\w]*[0-9a-z]*\.)+[a-z0-9][\-a-z0-9]{0,22}[a-z0-9])|((?=.{1,63}$)[0-9a-z][-\w]*))$

 # Note - remove all comments '(comments)' before runninig this regex
 # Find  \([^)]*\)  replace with nothing

 (?im)                                     # Case insensitive
 ^                                         # BOS

                                           # Local part
 (?= .{1,64} @ )                           # 64 max chars
 (?:
      (                                         # (1 start), Quoted
           " [^"\\]* 
           (?: \\ . [^"\\]* )*
           "
           @
      )                                         # (1 end)
   |                                          # or, 
      (                                         # (2 start), Non-quoted
           (?:
                [0-9a-z] 
                (?:
                     \.
                     (?! \. )
                  |                                          # or, 
                     [-!#\$%&'\*\+/=\?\^`\{\}\|~\w] 
                )*
           )?
           [0-9a-z] 
           @
      )                                         # (2 end)
 )
                                           # Domain part
 (?= .{1,255} $ )                          # 255 max chars
 (?:
      (                                         # (3 start), IP
           \[
           (?: \d{1,3} \. ){3}
           \d{1,3} \]
      )                                         # (3 end)
   |                                          # or,   
      (                                         # (4 start), Others
           (?:                                       # Labels (63 max chars each)
                (?= .{1,63} \. )
                [0-9a-z] [-\w]* [0-9a-z]* 
                \.
           )+
           [a-z0-9] [\-a-z0-9]{0,22} [a-z0-9] 
      )                                         # (4 end)
   |                                          # or,
      (                                         # (5 start), Localdomain
           (?= .{1,63} $ )
           [0-9a-z] [-\w]* 
      )                                         # (5 end)
 )
 $                                         # EOS

---

如何使[e-mail]成为有效的电子邮件ID – Mihir 2月7日，9：34

我认为规范希望将本地部分用引号引起来

或用 [0-9a-z]包裹。

I think the spec wants the local part to be either encased in quotes
or, to be encased by [0-9a-z].

但是，为了避开稍后并使 [e-mail] 有效，只需

将此组2替换为：

But, to get around the later and make [e-mail] valid, just
replace group 2 with this:

      (                             # (2 start), Non-quoted
           [0-9a-z] 
           (?:
                \.
                (?! \. )
             |                              # or, 
                [-!#\$%&'\*\+/=\?\^`\{\}\|~\w] 
           )*
           @

      )                             # (2 end)

新正则表达式

"(?im)^(?=.{1,64}@)(?:(\"[^\"\\\\]*(?:\\\\.[^\"\\\\]*)*\"@)|([0-9a-z](?:\\.(?!\\.)|[-!#\\$%&'\\*\\+/=\\?\\^`\\{\\}\\|~\\w])*@))(?=.{1,255}$)(?:(\\[(?:\\d{1,3}\\.){3}\\d{1,3}\\])|((?:(?=.{1,63}\\.)[0-9a-z][-\\w]*[0-9a-z]*\\.)+[a-z0-9][\\-a-z0-9]{0,22}[a-z0-9])|((?=.{1,63}$)[0-9a-z][-\\w]*))$"

新演示

https ：//regex101.com/r/ObS3QZ/5

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