等待C中中断的有效方法 [英] Efficient way to wait for an interrupt in C

问题描述

我在树莓派上使用WiringPi。我给它分配了一个中断函数，稍后再调用。我不确定在等Interupt打电话时该怎么办。

I am using WiringPi on a raspberry pi. With it I assign an interrupt function which is called later. I'm not sure what to do when waiting for the interupt to be called.

示例在（;;）中使用（自旋锁）例如

Examples use a (spinlock?) for (;;) e.g.

int main()
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        // really?
    }
    return 0;
}

我注意到睡眠也可以。不管睡眠如何，都会调用该中断

And I noticed that sleep works too. The interrupt is called regardless of the sleep

int main() 
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        sleep(1000000);
    }
    return 0;
}

使用最少的资源来保持程序运行的最佳实践是什么（例如

What is the best practise to keep the program running, using minimal resources (say if this were for a background demon)?

来自其他语言，我会以为 for（;;）会消耗资源。我想知道该怎么做或要做什么的指针（线程等）。

Coming from other languages, I would have thought for(;;) would eat up resources. I would like to know what to do or pointers on what to do (threads etc).

推荐答案

我最近不得不精确地做这个。我的理论是 KISS 。 sleep 被定义为使用最少的资源-使用它意味着我不必关心线程。

I recently had to do exactly this. My theory was KISS. sleep is written to use minimal resources by definition - and using it means I don't have to care about threads.

原始Raspberry Pi B上的简单，易读且没有可衡量的性能：

Simple, readable and no measurable performance hit on an original Raspberry Pi B:

int main() 
{
    // register interrupt
    wiringPiISR( 18, INT_EDGE_BOTH, &myInterrupt );

    for (;;) {
        sleep(UINT_MAX);
    }
    return 0;
}

请注意，使用UINT_MAX可以最大程度地减少for循环调用的次数-假设无符号的32位计时器延迟，这是WiringPi所使用的。

Note the use of UINT_MAX to minimise number of for loop calls - this assumes an unsigned 32-bit timer delay, which is what WiringPi uses.

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