期望脚本正则表达式不起作用 [英] expect script regex not working
本文介绍了期望脚本正则表达式不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
此脚本无法按预期工作:
This script is failing to work as expected:
#!/usr/bin/expect
set timeout 2
set server [lindex $argv 0]
set user [lindex $argv 1]
set password [lindex $argv 2]
set mac [lindex $argv 3]
set interface "po1"
spawn ssh $user@$server
expect "Password:"
send -- "$password\n"
expect "*>"
send "show mac address-table address $mac\n"
# 100 1cc1.de65.441c dynamic ip,ipx,assigned,other Port-channel43
expect -re { (\d+) *($mac) *(dynamic|static) *(.*) *(.*)} {
set interface $expect_out(5,string)
expect "*>"
send "show interface $interface status\n"
}
send "exit\n"
interact
发出上面的show mac命令后,输出包含一行,看起来像在其下方注释的那一行.但是以下的Expect -re块永远不会被命中,从而使其超时并发送退出命令.
After issuing the show mac command above, the output contains one line that looks like the one commented below it. but the following expect -re block is never hit, making it time out and send the exit command.
样本输出: 生成ssh user @ host 密码:
Sample output: spawn ssh user@host Password:
================= Host login banner =================
host>show mac address-table address 1cc1.de65.441c
Unicast Entries
vlan mac address type protocols port
---------+---------------+--------+---------------------+-------------------------
100 1cc1.de65.441c dynamic ip,ipx,assigned,other Port-channel43
host>exit
Connection to host closed.
推荐答案
您的正则表达式不正确,并且大括号内的替换不会发生.即$mac
不会被替换,因为它在花括号内.
Your regex is not correct and inside braces substitutions won't happen. i.e. $mac
won't be substituted as it is inside braces.
expect {
-re "\\d+\\s+$mac\\s+(dynamic|static)\\s+\\S+\\s+(\\S+)" { set interface $expect_out(2,string); # Add your further code}
}
这篇关于期望脚本正则表达式不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文