Bash正则表达式匹配不起作用 [英] Bash regex matching not working

问题描述

所以我有这个功能

function test(){
 local output="CMD[hahahhaa]"
 if [[ "$output" =~ "/CMD\[.*?\]/" ]]; then
  echo "LOOL"
 else
  echo "$output"
 fi;

}

尽管模式应该与$ output相匹配，但是在命令行中执行测试会输出$ output而不是"LOOL" ...

however executing test in command line would output $output instead of "LOOL" despite the fact that the pattern should be matching $output...

我做错了什么?

推荐答案

请勿使用引号""

if [[ "$output" =~ ^CMD\[.*?\]$ ]]; then

---

更新: (响应@frhd)

好吧，正则表达式运算符=~在其RHS上期望 unquoted 正则表达式，并且仅执行子字符串匹配，除非锚点^(输入的开始)和$(输入的末尾)还用于使其与整个LHS匹配.

Well, the regex operator =~ expects an unquoted regular expression on its RHS and does only a sub-string match unless the anchors ^ (start of input) and $ (end of input) are also used to make it match the whole of the LHS.

报价 ""会覆盖此行为，而是强制进行简单的字符串匹配，即匹配器从字面上查找所有这些字符\[.*?\].

Quotations "" override this behaviour and force a simple string match instead i.e. the matcher starts looking for all these characters \[.*?\] literally.

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