正则表达式匹配bash变量 [英] regex match bash variable

问题描述

我正在尝试修改bash脚本.脚本当前包含

I am trying to modify a bash script. The script current contains

print "<div class=\"title\">" $1 "</div>"

$ 1 可能如下所示:

Apprentice Historian (Level 1)
Historian (Level 4)
Master Historian (Level 7)

我想做的是添加一个名为"base"值的图像.我有这样的想法:

What i'd like to do is add an image which is named the "base" value. I had something like this in mind:

print "<div class=\"icon\"><imgsrc=\"icons\" $1 ".png\"></div><div class=\"title\">" $1 "</div>"

但是，在这种情况下，我希望 $ 1 只返回 Historian .我当时想我可以使用正则表达式来匹配和匹配 $ 1 并仅保留我需要的部分.

However, in this case I'd like $1 to only return Historian. I was thinking I could use a regex to match and on $1 and keep only the part I need.

(Apprentice|Master)?\s(.*)\s(\(Level \d\)) 

我知道我的正则表达式还不存在，理想情况下，学徒/大师将在他们自己的比赛组中，而不是与基地打成一片.而且我不知道如何匹配 $ 1 参数.

I know my regex isn't quite there, ideally apprentice/master would be in their own match group and not tied the base. And I don't know how to match on the $1 argument.

推荐答案

在bash中使用正则表达式匹配:

Using regex matching in bash:

for a in 'Apprentice Historian (Level 1)' 'Historian (Level 4)' 'Master Historian (Level 7)' ; do
    set "$a"
    echo " === $1 ==="
    [[ $1 =~ (Apprentice|Master)?' '?(.*)' ('Level' '[0-9]+')' ]] \
        && echo ${BASH_REMATCH[${#BASH_REMATCH[@]}-1]}
done 

棘手的部分是从BASH_REMATCH检索正确的成员.Bash不支持非捕获括号，因此Historian小于1或2.幸运的是，我们知道它是最后一个.

The tricky part is to retrieve the correct member from BASH_REMATCH. Bash does not support non-capturing parentheses, therefore Historian is either under 1 or 2. Fortunately, we know it is the last one.

这篇关于正则表达式匹配bash变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！