从Express中的静态文件中排除子目录 [英] Exclude sub directory from static files in express

问题描述

有什么方法可以从 express 4.8.5中的Express静态中间件中排除子目录.

Is there any way to exclude sub directory from express static middleware in express 4.8.5.

例如，如果我有:

app.use(express.static(__dirname + 'public'));

我的公共目录是这样的:

And my public directory is like this :

- public  
   - css
   - images
   - scripts
   - index.html
   - exclude_me
        - scripts
        - views
        - index.html

因此，我需要排除最后一个子目录以及用户执行操作的时间:

So I need to exclude last sub directory and when user does :

GET /exclude_me

它应该呼叫我的路线，而不是自动返回目录.

It should call my route rather than returning directory automatically.

我不能仅仅将其从公共目录中删除，因为它取决于其中的内容，因为 public 目录是有角度的应用程序，而 exclude_me 是另一个从中获取脚本的有角度的应用程序/exclude_me/scripts 和 AND ，来自/public/scripts .

I can't just remove it from public dir because it depends on stuff inside it because public directory is angular application and exclude_me is another angular application that fetches scripts from /exclude_me/scripts AND from /public/scripts.

我知道这有点让人困惑，但是它是这样，我不能仅仅将其从公共目录中删除，因为它不再看到需要的 public/scripts 并且我不能离开它因为那时我无法对其进行授权(所有授权均在 public/scripts 中)

I know it is little confusing but it is how it is and I cannot just remove it from public dir because it won't see public/scripts any more which are needed and I cannot leave it because I cannot authorize it then (all authorization is in public/scripts)

如果有更聪明的方法，请随时告诉我:)

If there is some smarter way to do this, feel free to let me know :)

推荐答案

您可以添加自己的中间件.这是我为排除某些文件夹所做的事情:

You can add your own middleware. Here's what I did to exclude some folders:

app.use('/public', (req, res, next) => {
  if (env !== 'development') {
    var result = req.url.match(/^\/js\/(maps|src)\/.+\.js$/)
    if (result) {
      return res.status(403).end('403 Forbidden')
    }
  }
  next()
})
app.use('/public', express.static(path.join(__dirname, '/public')))

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