如果我从未在打开的文件流上调用`close`会发生什么? [英] What happens if I never call `close` on an open file stream?

问题描述

下面是相同情况的代码.

Below is the code for same case.

#include <iostream>
#include <fstream>

using namespace std;

int main () {
    ofstream myfile;
    myfile.open ("example.txt");
    myfile << "Writing this to a file.\n";
    //myfile.close();
    return 0;
}

如果取消注释myfile.close()行，会有什么区别?

What will be the difference if I uncomment the myfile.close() line?

推荐答案

没有区别.文件流的析构函数将关闭文件.

There is no difference. The file stream's destructor will close the file.

您也可以依靠构造函数打开文件，而不用调用open().您的代码可以简化为:

You can also rely on the constructor to open the file instead of calling open(). Your code can be reduced to this:

#include <fstream>

int main()
{
  std::ofstream myfile("example.txt");
  myfile << "Writing this to a file.\n";
}

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