获取最新的N个文件并删除其余文件 [英] Get most recent N files and delete the rest

问题描述

我正在尝试编写一种方法，该方法从文件夹获取文件，按创建时间对其进行排序，获取最新的前五个文件，然后删除其余的文件.

I am trying to write a method that gets files from a folder, orders it by creation time, takes the top five latest files and deletes the rest.

任何帮助将不胜感激，我拥有的代码如下:

Any help will be much appreciated, my code that i have is as follows:

DirectoryInfo Dir = new DirectoryInfo(DirectoryPath);
FileInfo[] FileList = Dir.GetFiles("*.*", SearchOption.AllDirectories);
var x = FileList.OrderByDescending(file => file .CreationTime).Take(5);

如何修改此代码以删除所有其他文件?

How do I amend this code to delete all the other files?

推荐答案

当您保留第一个N并与其余的做其他事情时，最好遍历所有内容，并抛出第一个N进入另一个列表，同时调用其余的Delete().

As you are keeping the first N and doing something else with the rest, it would be better to just loop through everything, throwing the first N into a separate list while calling Delete() on the rest.

var query = fileList.OrderByDescending(file => file.CreationTime);
var keepers = new List<FileInfo>();
var i = 0;
foreach (var file in query)
{
    if (i++ < N)
    {
        keepers.Add(file);
    }
    else
    {
        file.Delete();
    }
}

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