tkinter-在askopenfile期间检索文件名 [英] tkinter - retrieve file name during askopenfile

问题描述

我有一个使用Python和tkinter制作的文本编辑器.

I have a text editor made with Python and tkinter.

这是我的打开文件"方法:

This is my 'open file' method:

def onOpen(self):
        file = askopenfile(filetypes=[("Text files", "*.txt")])
        txt = file.read()
        self.text.delete("1.0", END)
        root.title(file)
        self.text.insert(1.0, txt)
        file.close()

我想将窗口标题设置为等于文件名.目前，我正在使用任何askopenfile返回的文件名，但是返回的示例如下:

I would like to set the window title equal to the file name. At the moment I'm using whatever askopenfile return as the file name, but this returns for example:

< _io.TextIOWrapper名称='/Users/user/Desktop/file.txt'mode ='r'encoding ='UTF-8'>

<_io.TextIOWrapper name='/Users/user/Desktop/file.txt' mode='r' encoding='UTF-8'>

这当然不是很好.我想要任何askopenfilename都会返回.但是，如果我调用askopenfile和askopenfilename，则用户必须两次使用打开文件"对话框.

This, of course, isn't very nice. I would like whatever askopenfilename would return. But if I call askopenfile and askopenfilename the user has to use the 'open file' dialog twice.

没有第二个对话框，有没有办法检索文件名?

Is there any way to retrieve the file name without the second dialog?

如果不是，则有人进行RegEx过滤以滤除文件名.如果您对RegEx满意，最好的文件名当然就是'file.txt'而不是'/Users/user/Desktop/file.txt'.无论哪种方式都很好.

If not, does anyone a RegEx to filter out the file name. if you're good with RegEx, the nicest file name would of course be just 'file.txt' not '/Users/user/Desktop/file.txt'. Either way it's fine, though.

推荐答案

您正在传递文件对象，因此您可以看到对文件对象的引用作为标题，您可以使用name = root.title(file.name)从文件对象中获取名称.

You are passing the file object so you see the reference to the file object as the title, you can get the name from the file object with name = root.title(file.name).

如果只想使用基本名称，请使用 os. path.basename :

If you want just the base name use os.path.basename:

import os
name = os.path.basename(file.name)

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