如何快速过滤具有其他数组值的结构数组? [英] How to filter an array of structs with value of other array in swift?

问题描述

我已经搜索了这个问题，但是没有找到使用最新版本的Xcode和Swift的解决方案.我使用三个数组:

I have searched for this issue and I did not find any solution that is working for me using the latest version of Xcode and Swift. I use three arrays:

1. baseArray[Meal]: array filled with every meal. Not locally saved.

2. favoritesArray[Favorite]: with names of all favorite meals, locally saved by the user with NSKeyedArchiver.
3. filteredArray[Meal]: baseArray but filtered for searchterm. In code: 

    (filteredArray = baseArray.filter { $0.type == searchtext }}

我使用tableView中的最后一个数组.如果他们想查看所有餐点，则filteredArray与baseArray相同.

I use the last array in the tableView. If they want to see all meals, the filteredArray is the same as the baseArray.

我的问题:我怎么能得到所有喜欢的饭菜的filteredArray(所以Meal.title == Favorite.name在哪里).如何结合三个阵列?

My question: how can I get the filteredArray that it has all favorite meals (so where Meal.title == Favorite.name). How do i combine three arrays?

上周我尝试了很多选择，但没有一个奏效..希望您能帮到我！

I have tried a lot of options in the last week, but none has worked.. I hope You can help me out!!

推荐答案

这就是您想要的:

struct Meal {
  let title: String
}

struct Favorite {
  let name: String
}

let meal1 = Meal(title: "Soup")
let meal2 = Meal(title: "Stew")
let meal3 = Meal(title: "Pizza")

let favorite1 = Favorite(name: "Stew")

let baseArray = [meal1, meal2, meal3]
let favoritesArray = [favorite1]

let favoriteNames = favoritesArray.map { $0.name }

let filteredArray = baseArray.filter { favoriteNames.contains($0.title) }

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