查找并切出python子字符串 [英] Find and cut out a python substring

问题描述

这就是我想要做的:

我的字符串很长:

s = asdf23rlkasdfidsiwanttocutthisoutsadlkljasdfhvaildufhblkajsdhf

我想剪切出子字符串:iwanttocutthisout

I want to cut out the substring: iwanttocutthisout

我将遍历一个循环，并且每次迭代时s的值都会改变.每次迭代唯一不变的是要删除的子字符串的开头和结尾:iwant和thisout.

I will be iterating through a loop and with each iteration the value of s will change. The only thing that will stay the same with each iteration is the begining and end of the substring to be cut out: iwant and thisout.

在给定这些参数的情况下，如何剪裁子字符串?

How can I cut out the substring, given these parameters?

感谢您的帮助！

推荐答案

您可以分别在iwant(+len(iwant)排除iwant)和thisout的出现索引之间进行切片所以:

You can do a slice between the index of occurance of iwant (+len(iwant) to dis-include iwant) and thisout respectively, like so:

>>> s = "asdf23rlkasdfidsiwanttocutthisoutsadlkljasdfhvaildufhblkajsdhf"
>>> s[s.index("iwant")+len("iwant"):s.index("thisout")]
'tocut'

钻石般地:

"asdf23rlkasdfids(iwanttocut)thisoutsadlkljasdfhvaildufhblkajsdhf"
                 ^          ^ 
                 |          |
            index("iwant")  |
                           index("thisout")

请注意，这两个索引之间的切片(从开始算起)如何得到iwanttocut.添加len("iwant")将导致:

Notice how slicing between these two indexes (beginning inclusive) would get iwanttocut. Adding len("iwant") would result in:

"asdf23rlkasdfidsiwant(tocut)thisoutsadlkljasdfhvaildufhblkajsdhf"
                      ^     ^ 
                 /----|     |
     index("iwant")         |
                           index("thisout")

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