Python:在字符串中查找子字符串并返回子字符串的索引 [英] Python: Find a substring in a string and returning the index of the substring
问题描述
我有:
-
一个函数:
def find_str(s,char)
和一个字符串:生日快乐
,
我基本上想输入py
并返回 3
但我会继续 2
返回。
I essentially want to input "py"
and return 3
but I keep getting 2
to return instead.
代码:
def find_str(s, char):
index = 0
if char in s:
char = char[0]
for ch in s:
if ch in s:
index += 1
if ch == char:
return index
else:
return -1
print(find_str("Happy birthday", "py"))
不确定是什么问题!
推荐答案
理想情况下,您可以使用 str.find 或 str.index 像疯狂的刺猬说。但是你说你不能......
Ideally you would use str.find or str.index like demented hedgehog said. But you said you can't ...
你的问题是你的代码只搜索你的搜索字符串的第一个字符(第一个字符)是索引2 。
Your problem is your code searches only for the first character of your search string which(the first one) is at index 2.
你基本上是说 char [0]
是否在 s
,增加 index
直到 ch == char [0]
我测试时返回3但是它还是错的这是一种方法。
You are basically saying if char[0]
is in s
, increment index
until ch == char[0]
which returned 3 when I tested it but it was still wrong. Here's a way to do it.
def find_str(s, char):
index = 0
if char in s:
c = char[0]
for ch in s:
if ch == c:
if s[index:index+len(char)] == char:
return index
index += 1
return -1
print(find_str("Happy birthday", "py"))
print(find_str("Happy birthday", "rth"))
print(find_str("Happy birthday", "rh"))
它产生以下输出:
3
8
-1
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