简单的PHP:从表单输入获取变量 [英] Simple PHP: getting variable from a form input
问题描述
我不能真正使用PHP，从我在教程中看到的内容来看，它应该可以工作，但是不能:
I can't really use PHP and from what I've seen in tutorials this should work, but it doesn't:
<html>
<head></head>
<body>
<form>
<input type='text' name="name" value='myName'>
</form>
<p>
<?php
$name = $_POST['name'];
echo $name
?>
</p>
</body>
</html>
我是否有理由无法获得name的值? 很抱歉问这样一个简单的问题...
Is there a reason I can't get the value of name? Sorry for asking such a simple question...
这是小提琴 http://jsfiddle.net/DCmu5/1/，所以，请尝试使用您所说的内容，然后在回答有效之前，先将其发送给我
here is the fiddle http://jsfiddle.net/DCmu5/1/, so, please try what you said and send it to me only when it works before answering
推荐答案
PHP是一种服务器端语言，因此您需要提交表单才能访问其变量.
PHP is a server-side language, so you'll need to submit the form in order to access its variables.
由于您未指定method，因此假设使用GET，因此您需要$_GET超全局变量:
Since you didn't specify a method, GET is assumed, so you'll need the $_GET super-global:
echo $_GET['name'];
使用$_POST可能更好(因为这样可以避免直接在URL中传递值.因此，您可以将method属性添加到<form>元素中，如下所示:
It's probably better though, to use $_POST (since it'll avoid the values being passed in the URL directly. As such, you can add method attribute to your <form> element as follows:
<form method="post">
<input type='text' name="name" value="myName" />
<input type="submit" name="go" value="Submit" />
</form>
注意，我也添加了一个提交按钮，以达到良好的效果，但这不是必需的.只需在文本框内单击return即可提交表单.
Notice I also added a submit button for good measure, but this isn't required. Simply hitting return inside the textbox would submit the form.
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