从PHP的外部获取变量 [英] Get variables from the outside, inside a function in PHP

问题描述

我试图弄清楚如何使用一个已经在函数外部设置的变量。有没有办法做到这一点？我试图将该变量设置为全局，但它似乎没有按预期工作。

我的代码的一个简单示例

  $ var ='1'; 
 
 function（）{
 $ var + 1; 
返回$ var; 
} 
  

我想要这个，要返回2的值。

解决方案

您需要在函数中使用全局关键字。
http://php.net/manual/en/language.variables.scope.php

编辑（尴尬我忽视了这一点，感谢评论者）

...并将结果存储在某处

  $ var ='1'; 
 function（）{
 global $ var; 
 $ var + = 1; //你确定你想同时改变$ var 
的值$ return $ var; //并返回值？ 
} 
  

I'm trying to figure out how i can use a variable, that has been set outside a function, inside. Is there any way of doing this? I've tried to set the variable to "global" but it doesn't seems to work out as expected.

A simple example of my code

$var = '1';

function() {
$var + 1;
return $var;
}

i want this, to return the value of 2.

解决方案

You'll need to use the global keyword inside your function. http://php.net/manual/en/language.variables.scope.php

EDIT (embarrassed I overlooked this, thanks to the commenters)

...and store the result somewhere

$var = '1';
function() {
    global $var;
    $var += 1;   //are you sure you want to both change the value of $var
    return $var; //and return the value?
}

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