R更新功能，如何删除与预定变量相关的所有变量 [英] R update function, how to drop all the variables that are related to a pre-specified variable

问题描述

我有一个R公式对象:

 formula1 <- y ~ x1 + x2 + x3 + x1:x2

我想通过删除所有与x1相关的变量来更新此公式对象.那就是x1和x1:x2.

I want to update this formula object by dropping all x1-related variables. That is x1 AND x1:x2.

如果我使用更新功能，

 update(formula1,.~.-x1)

我得到:

 y ~ x2 + x3 + x1:x2

这不是我想要的.在实践中，我不知道在Formula1对象中定义了多少个x1交互作用.

This is not what I want. In practice, I do not know how many interaction effects of x1 are defined in the formula1 object.

是否有获取

 y ~ x2 + x3

推荐答案

以下是删除包含所有存在该术语的所有相互作用的术语的功能:

Here's a function to remove a term including all interactions in which the term is present:

remove_terms <- function(form, term) {
  fterms <- terms(form)
  fac <- attr(fterms, "factors")
  idx <- which(as.logical(fac[term, ]))
  new_fterms <- drop.terms(fterms, dropx = idx, keep.response = TRUE)
  return(formula(new_fterms))
}

应用功能

formula1 <- y ~ x1 + x2 + x3 + x1:x2

# the term that should be removed
to_remove <- "x1"

remove_terms(formula1, to_remove)
# y ~ x2 + x3

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